Skip to main content
Course and syllabus guidance

University Physics IV · topic UPIV-14.03

Fundamental interactions and their gauge bosons

Connect the ideas, make your working visible, and test the result. Use the hints when you need a starting point; open the full solution after your attempt.

Further practice

Work through a fresh case before tackling the extension.

Further practice · 01

Interactions and their gauge bosons: predict a finite change

A gauge boson is the spin-1 field that a local phase symmetry forces into existence, and the mass it carries sets how far the interaction it mediates can reach — unless, as for the massless gluon, confinement ends that reach first. Use the supplied topic model Y_out = 10^u, where Y_out is MEDIATOR MASS Mc² (MeV). The output symbol Y_out is distinct from all input symbols. ^ denotes a power; π = 3.141592653589793. u is Mediator mass log₁₀(Mc²/MeV), dimensionless. Keep v (Separation log₁₀(r/fm)) = 0 fixed. For this exercise use only 1.80375 ≤ u ≤ 4.79625 on this continuous branch. A grid of test settings is an input restriction for this exercise, not by itself a claim of physical quantisation. This calculation retains the topic model's stated assumptions; it does not extend them to a different physical setup. Calculate Y_out at u = 2.4621 and 2.88105. Find the signed output change ΔY_out and the average sensitivity ΔY_out/Δu across this interval. State whether the response increases or decreases; distinguish this interval average from a derivative at one point.

Explore the question data

MEDIATOR MASS Mc² against u

Predictions from the supplied Interactions and their gauge bosons model, with all other inputs fixed as stated in the question. 5 calibration points support a trend comparison; they are not measured data or a straight-line law.

Vertical axis (y): MEDIATOR MASS Mc² / MeV

MEDIATOR MASS Mc² against uPredictions from the supplied Interactions and their gauge bosons model, with all other inputs fixed as stated in the question. 5 calibration points support a trend comparison; they are not measured data or a straight-line law. Horizontal axis: u: Mediator mass log₁₀(Mc²/MeV). Vertical axis: MEDIATOR MASS Mc² / MeV. Exact values are available in the data table below.-24361.44e43.13e44.82e46.51e41.6842.4923.34.1084.916xy

Horizontal axis (x): u: Mediator mass log₁₀(Mc²/MeV)

Axes show the supplied calibration interval; the origin may lie outside the plot.

Reading 1u: Mediator mass log₁₀(Mc²/MeV): 1.804MEDIATOR MASS Mc² / MeV: 63.64
Read the exact data as a table
MEDIATOR MASS Mc² against u — supplied values
u: Mediator mass log₁₀(Mc²/MeV)MEDIATOR MASS Mc² / MeV
1.8037563.64290574262721
2.551875356.34855330614226
3.31995.2623149688789
4.04812511171.847531298365
4.7962562553.267470760664

These are the supplied values, not a worked answer. No fitted trend is drawn.

Show a hint

Substitute each value of u separately while keeping every other input fixed, then subtract in the same order.

Reveal the worked solution
  1. At u = 2.4621, substitute into Y_out = 10^u: Y₀ = 289.801 MeV.
  2. At u = 2.88105, the same fixed-parameter model gives Y₁ = 760.414 MeV.
  3. Signed change: ΔY_out = Y₁ − Y₀ = 470.613 MeV; the input change is Δu = 0.41895.
  4. Average sensitivity is ΔY_out/Δu = 1123.31 MeV per unit input. Its positive sign means that this response increases over the specified interval.
  5. This is a secant slope between two settings. It equals a point derivative only for a locally linear relation or in a justified small-interval limit.

Answer Y₀ = 289.801 MeV, Y₁ = 760.414 MeV; ΔY_out = 470.613 MeV; average sensitivity = 1123.31 MeV per unit input.

Compare the assumptions, method and units with your attempt. Explain any correction before trying another question.

Extra challenging questions

Work through the linked stages and explain what each result means.

Extra challenging · 01

Interactions and their gauge bosons: infer an input with uncertainty

A gauge boson is the spin-1 field that a local phase symmetry forces into existence, and the mass it carries sets how far the interaction it mediates can reach — unless, as for the massless gluon, confinement ends that reach first. Use the supplied topic model Y_out = 10^u, where Y_out is MEDIATOR MASS Mc² (MeV). The output symbol Y_out is distinct from all input symbols. ^ denotes a power; π = 3.141592653589793. u is Mediator mass log₁₀(Mc²/MeV), dimensionless. Keep v (Separation log₁₀(r/fm)) = 0 fixed. For this exercise use only 1.80375 ≤ u ≤ 4.79625 on this continuous branch. A grid of test settings is an input restriction for this exercise, not by itself a claim of physical quantisation. This calculation retains the topic model's stated assumptions; it does not extend them to a different physical setup. A reading gives Y_out = 4257.6994 MeV, with a bounded reading uncertainty ±629.11 MeV. Treat the model and all fixed inputs as exact for this exercise; the bound is not a standard deviation. First estimate the unknown u by straight-line interpolation between the two endpoint predictions. Then solve the actual model on the stated branch to an absolute input tolerance of 0.00029925, using a numerical bracket if required. Find the full input interval consistent with the bounded reading uncertainty and compare it with a symmetric input-error assumption. Do not assume that the supplied calibration points prove monotonicity outside this branch.

Explore the question data

MEDIATOR MASS Mc² against u

Predictions from the supplied Interactions and their gauge bosons model, with all other inputs fixed as stated in the question. 5 calibration points support a trend comparison; they are not measured data or a straight-line law.

Vertical axis (y): MEDIATOR MASS Mc² / MeV

MEDIATOR MASS Mc² against uPredictions from the supplied Interactions and their gauge bosons model, with all other inputs fixed as stated in the question. 5 calibration points support a trend comparison; they are not measured data or a straight-line law. Horizontal axis: u: Mediator mass log₁₀(Mc²/MeV). Vertical axis: MEDIATOR MASS Mc² / MeV. Exact values are available in the data table below.-24361.44e43.13e44.82e46.51e41.6842.4923.34.1084.916xy

Horizontal axis (x): u: Mediator mass log₁₀(Mc²/MeV)

Axes show the supplied calibration interval; the origin may lie outside the plot.

Reading 1u: Mediator mass log₁₀(Mc²/MeV): 1.804MEDIATOR MASS Mc² / MeV: 63.64
Read the exact data as a table
MEDIATOR MASS Mc² against u — supplied values
u: Mediator mass log₁₀(Mc²/MeV)MEDIATOR MASS Mc² / MeV
1.8037563.64290574262721
2.551875356.34855330614226
3.31995.2623149688789
4.04812511171.847531298365
4.7962562553.267470760664

These are the supplied values, not a worked answer. No fitted trend is drawn.

Show a hint

The model's endpoint predictions bracket the reading. Solve Y_out(u) = Y_measured and then solve again at Y_measured − u and Y_measured + u; a nonlinear inverse can give unequal input deviations.

Reveal the worked solution
  1. Endpoint predictions are Y_out(1.80375) = 63.6429 MeV and Y_out(4.79625) = 62553.3 MeV. The target lies between them. On the selected branch the response is strictly increasing.
  2. Endpoint interpolation gives u_line = 1.80375 + (4257.7 − 63.6429)(4.79625 − 1.80375)/(62553.3 − 63.6429) = 2.00459. This estimates the inverse of the endpoint chord, rather than assuming that chord is the physical model.
  3. Use the actual equation, not the chord, and bracket its root. Evaluating the midpoint and retaining the sign-changing half-interval gives u = 3.62917; substituting back gives Y_out = 4257.6994 MeV.
  4. The interpolation error in the input is |u_line − u| = 1.62458. This is larger than the requested numerical tolerance.
  5. Invert both limits Y_out = 3628.5894 MeV and 4886.8094 MeV. Sort the roots even if the response decreases: 3.55974 ≤ u ≤ 3.68903.
  6. The lower and upper input deviations are 0.0694372 and 0.0598504. They differ because the inverse response is nonlinear; a symmetric error bar would only be a local approximation. This interval includes reading uncertainty only, not model error or uncertainty in fixed inputs.

Answer u ≈ 3.62917; compatible interval [3.55974, 3.68903]. Endpoint interpolation gives 2.00459.

Compare the assumptions, method and units with your attempt. Explain any correction before trying another question.