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MYP Physics · Unit 03

Forces

Contact and non-contact interactions, free-body diagrams, mass and weight, Newton's laws, friction, elasticity, and equilibrium.

21
questions
19
total marks
5
mapped topics
01
Criterion AYears 1–2multiple choicerecall

Forces on a rising lift

3 marks

A lift is moving upward at constant speed. Which statement about the lift is correct?

  1. A

    The upward force is greater than its weight.

  2. B

    Its weight is greater than the upward force.

  3. C

    The upward force equals its weight.

  4. D

    No forces act because its speed is constant.

  1. a

    Select and explain Select the correct statement and connect it to the lift's motion.

    3
    Ready to self-mark?Reveal the detailed answer3 marks

    Mark-by-mark answer

    Correct choiceC

    1. Selects option C: the upward force on the lift equals its weight.

    2. States that constant velocity means zero acceleration.

    3. Uses zero resultant force to conclude that the upward force balances the downward weight.

Build deeper understandingReveal the teacher insight

Deeper learning cue

Counter the common idea that an upward-moving object must have a larger upward force by separating velocity from acceleration.

02
Criterion CYears 2–4data analysisdemanding

Finding cart mass from force data

8 marks

A cart is pulled along a horizontal track. The same resistive force acts in every run.

Applied force and measured acceleration
Applied force / NAcceleration / m s⁻²
1.00.20
2.00.60
3.01.00
4.01.40
5.01.80
  1. a

    Determine Use the change across the data to determine the cart's mass. Show how the units support your answer.

    3
    Ready to self-mark?Reveal the detailed answer3 marks

    Mark-by-mark answer

    1. Finds slope ΔF ÷ Δa = (5.0 − 1.0) ÷ (1.80 − 0.20).

    2. Obtains mass = 2.5 kg from F = ma.

    3. Recognises N per m s⁻² is equivalent to kg.

  2. b

    Calculate Use one data row to calculate the resistive force.

    3
    Ready to self-mark?Reveal the detailed answer3 marks

    Mark-by-mark answer

    1. Uses applied force − resistive force = ma.

    2. For example, at 3.0 N calculates ma = 2.5 × 1.00 = 2.5 N.

    3. Obtains resistive force = 0.50 N, opposing the motion.

  3. c

    Explain Explain why a graph of applied force against acceleration would not pass through the origin.

    2
    Ready to self-mark?Reveal the detailed answer2 marks

    Mark-by-mark answer

    1. The applied force must first balance the approximately constant resistive force.

    2. Therefore zero acceleration occurs at a non-zero applied force of about 0.50 N.

Build deeper understandingReveal the teacher insight

Deeper learning cue

Plotting force on the vertical axis makes the slope equal to mass and the intercept equal to the resistive force.

03
Criterion DYears 4–5extended responsediscriminating

Grip, rolling resistance, and a wheelchair tyre

8 marks

A school is choosing wheelchair tyres. Tyre P needs an average push of 18 N on a smooth floor and 31 N on carpet; it stops in 1.8 m on a wet ramp. Tyre Q needs 23 N on the floor and 38 N on carpet; it stops in 1.2 m on the same wet ramp. Both meet the load rating.

  1. a

    Interpret Explain what the push-force and stopping-distance evidence suggests about the two tyres.

    3
    Ready to self-mark?Reveal the detailed answer3 marks

    Mark-by-mark answer

    1. Explains that P has lower rolling resistance because it requires less force on both surfaces.

    2. Explains that Q provides greater wet-ramp grip because its stopping distance is shorter.

    3. Recognises that the evidence shows a trade-off rather than one tyre being best in every respect.

  2. b

    Recommend Recommend a tyre for a route that includes carpet and a short wet ramp. Justify the choice using physics and user needs.

    3
    Ready to self-mark?Reveal the detailed answer3 marks

    Mark-by-mark answer

    1. Makes a clear recommendation that is consistent with a stated priority.

    2. Uses at least two relevant numerical comparisons from the evidence.

    3. Balances effort or fatigue against control and stopping safety for the user.

  3. c

    Propose Propose one further test needed before a final purchasing decision and explain why it matters.

    2
    Ready to self-mark?Reveal the detailed answer2 marks

    Mark-by-mark answer

    1. Proposes a relevant controlled test such as durability, side-slope grip, different user loads, or repeated wet braking.

    2. Connects the test to a limitation in the current evidence or a real user requirement.

Build deeper understandingReveal the teacher insight

Deeper learning cue

Criterion D quality comes from explicit priorities and limitations, not from choosing a predetermined tyre.

More focused practice

Seven quick mastery questions

Open one task at a time, reveal the worked reasoning, then mark it mastered or save it to revisit.

18

Criterion C

Extract mass and friction from acceleration data

12 marks · discriminatingOpen question →
Reference subsectionMapped lessons for this unit
MYP-03.01

Force, mass, and weight

Separate an object's properties from interactions acting on it and use a consistent force vocabulary.

Open lesson →
MYP-03.02

Free-body diagrams and resultants

Choose a system boundary, draw only external forces, and connect the resultant to the motion change.

Open lesson →
MYP-03.03

Newton's laws of motion

Criterion A focus: use a law to predict an outcome, then compare the prediction with evidence.

Open lesson →
MYP-03.04

Friction, drag, and terminal behaviour

Criterion D prompt: choose a surface or shape by balancing grip, wear, energy loss, and safety.

Open lesson →
MYP-03.05

Equilibrium and balanced forces

Design a repeatable balance test and explain why zero resultant does not require zero forces.

Open lesson →