State the exact numerical relationship between temperature T in kelvin and temperature θ in degrees Celsius. Convert 20.00 °C to kelvin and 250.00 K to Celsius. An object warms by 15.0 °C. State the increase in kelvin and explain why applying an absolute-temperature offset to that increase is wrong. Explain why doubling 20.00 °C does not double an ideal gas's absolute temperature.

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T/K = θ/°C + 273.15; 293.15 K; −23.15 °C; increase 15.0 K. Offsets cancel in a difference. Doubling 293.15 K gives 586.30 K, whereas 40.00 °C is 313.15 K. Recall the exact relation T/K = θ/°C + 273.15 (1). Calculate 293.15 K (1). Calculate −23.15 °C (1). State 15.0 K and explain cancellation of the offset (1). Double the absolute temperature to 586.30 K (1), and contrast with 40.00 °C = 313.15 K rather than claiming doubling Celsius doubles absolute temperature (1).

Convert values, not intervals

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