MYP Physics · 02 · data analysis
A delivery robot changes pace
Motion · Original GioPhysics question with a detailed, mark-by-mark answer guide.
- Demand
- routine
- Marks
- 7
- Topics
- 2
- Answer
- Complete
A delivery robot moves in a straight corridor. Its position is measured from a fixed doorway.
| Time / s | Position / m |
|---|---|
| 0 | 0 |
| 2 | 3 |
| 4 | 6 |
| 6 | 6 |
| 8 | 2 |
- a
Calculate Calculate the robot's velocity from 0 s to 4 s.
2 marks - b
Interpret Describe the motion from 4 s to 8 s, including direction.
3 marks - c
Compare Compare the robot's speed before and after the stop.
2 marks
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a
Calculate Calculate the robot's velocity from 0 s to 4 s.
Read the data before explaining it. Quote the relevant values or trend, show the comparison or calculation, and then connect that numerical evidence to the physical conclusion—including uncertainty or anomalies when they matter.
- 1
Uses velocity = change in position ÷ change in time.
- 2
Obtains (6 − 0) ÷ 4 = +1.5 m s⁻¹.
b
Interpret Describe the motion from 4 s to 8 s, including direction.
Read the data before explaining it. Quote the relevant values or trend, show the comparison or calculation, and then connect that numerical evidence to the physical conclusion—including uncertainty or anomalies when they matter.
- 1
States that the robot is stationary from 4 s to 6 s because its position is unchanged.
- 2
States that it then moves back toward the doorway from 6 s to 8 s.
- 3
Calculates or states the return velocity as (2 − 6) ÷ 2 = −2.0 m s⁻¹.
c
Compare Compare the robot's speed before and after the stop.
Read the data before explaining it. Quote the relevant values or trend, show the comparison or calculation, and then connect that numerical evidence to the physical conclusion—including uncertainty or anomalies when they matter.
- 1
Compares magnitudes 1.5 m s⁻¹ and 2.0 m s⁻¹.
- 2
Concludes that the robot moves faster after the stop, by 0.5 m s⁻¹.
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