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Statics · free game

Counterweight Crane

Slide the counterweight so the resultant of every weight stays inside the outrigger base. One control, one equation.

Session0

d = 0.25 ma = 7.00 mR_rear = 33.5 kNR_front = 25.3 kNx̄ = −0.17 mrear −1.2front +1.2
Lift 01 · Take-Up

The hook load grows as the rope takes up — walk the counterweight out to match it.

Counterweight d0.25 m

Simple definition
A body stays put when its forces and its turning effects both cancel, which lands the resultant inside its base.
Example
A 4 t counterweight 2.8 m behind the mast balances a 1.6 t load 7 m out, so the crane does not tip.
How the physics works
Moment balanceΣM_O = Σ Wᵢ(xᵢ − x_O)

Taking moments about the mast, the counterweight turns the rig back with W_c·d while the jib, the ice and the hook turn it forward. The readout is that sum, live.

Resultant positionx̄ = Σ Wᵢxᵢ / Σ Wᵢ

Divide the net moment by the total weight and you get the line of action of the single equivalent force — the same weighted average that locates a centre of mass. The rig stands only while that line falls between the pads.

Distributed loadsuniform wL at L/2 · triangular ½w₀L at 2L/3

The jib carries its own weight uniformly, so it becomes one force at its centroid. The ice thickens towards the tip, so its resultant sits two thirds of the way out — much further than a uniform strip of the same peak, which is why lift 03 bites.

Support reactionsR_front = ΣW(x̄ + r)/(f + r)

Take moments about the rear pad and one unknown disappears; ΣF_y = 0 then hands you R_rear = ΣW − R_front. The bars on the pads are those two numbers drawn to scale.

Why it movesd(t) = [W_p(t)·a(t) + ΣM_fixed] / W_c

While the rope takes up, W_p climbs from zero. While the trolley runs out, a grows. Both make the balancing distance a function of time, so a correct answer at t = 0 is wrong two seconds later.

Common slipbase centre = (f − r)/2

Balancing the mast is not balancing the base. When the front leg is shorter than the rear one, the safest lift leaves a deliberate backward moment rather than a zero one.

Game 09 · Statics learning guide

Turn the playthrough into a physics lesson.

Learning objectivePosition a crane counterweight so clockwise and anticlockwise moments balance throughout a lift.

01

What you will learn

  • A moment equals force times perpendicular distance from the pivot.
  • Static equilibrium requires zero resultant force and zero resultant moment.
  • Moving a load changes its turning effect even when its weight is unchanged.

02

How to play

  1. Read the load and boom geometry for the current lift.
  2. Move the counterweight until the moment display is balanced.
  3. Run the lift and adjust before the crane reaches its tipping limit.

03

Quick classroom check

If the load moves twice as far from the pivot and both weights stay unchanged, how must the counterweight distance change to keep balance?

Suitable forSecondary physics · moments and static equilibrium

Continue this topic

Move from play to explanation and exam-style practice.

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