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Optics · free physics game

Focus Rescue

Slide one optic until the beacon comes into focus where the brief wants it. Nothing is faked: the image is drawn wherever 1/f = 1/dₒ + 1/dᵢ puts it.

Score0/ 500

020406080100120bench · centimetresplatebeaconrealoff by 6.9 cm‹ Drag the lens ›dₒ = 52.0 cmdᵢ = 21.1 cmLevel 1 of 5 · Thin-lens equationLand a sharp image on the plate. Any size counts.1/15.0 = 1/52.0 + 1/21.1 cm⁻¹Focus lock0%m = −0.41 · Δ = 6.92 cmImage forms 6.9 cm short of the plate.
Lens
Position 62.00 cm
Simple definition
One equation places every image: 1/f = 1/dₒ + 1/dᵢ, and m = −dᵢ/dₒ sets how big it is and which way up.
Example
A lens with f = 20 cm and the beacon 30 cm away throws its image 60 cm out, twice as tall and upside down.
How the physics works

Every frame the game turns the optic position into an object distance dₒ, solves dᵢ = f·dₒ/(dₒ − f), and draws the image exactly there. If you can predict dᵢ on paper you can place the optic first time.

  • Where it lands. 1/f = 1/dₒ + 1/dᵢ. Push dₒ down toward f and the denominator collapses, so dᵢ sprints off to infinity.
  • How big, which way up. m = −dᵢ/dₒ = hᵢ/hₒ. A real image (dᵢ > 0) always has negative m, so it hangs upside down.
  • Two answers, not one. Fix the beacon-to-plate distance L = dₒ + dᵢ and the equation becomes dₒ² − Ldₒ + fL = 0. Its two roots are the two lens positions that both give a sharp image, and their magnifications are exact reciprocals — that is levels 2 and 3. Real roots need L ≥ 4f, which is why one lens in level 1 simply cannot reach.
  • Virtual and upright. Bring the beacon inside f and dᵢ goes negative: the image jumps to the object side, turns upright, and cannot be caught on a plate. That is a magnifying glass, and level 4 asks for one at the relaxed eye’s near point of 25 cm.
  • Mirrors use the same equation with f = R/2, except dₒ and dᵢ are measured on the same side, so the image comes back toward the beacon. Two lenses in a tube extend the same algebra to a telescope, where the angular magnification is M = f_o/f_e with the tube length f_o + f_e.
  • Why fine tuning is hard on some settings. Differentiating gives d(dᵢ)/d(dₒ) = −m², so near a magnifying conjugate the image moves m² times faster than the optic. A shrinking setting is calm; an enlarging one is twitchy.

Conventions: distances in centimetres, dₒ > 0 in front of the optic, dᵢ > 0 for a real image, f > 0 for a converging lens or concave mirror. The clear aperture is taken as 3.0 cm, which is what sets the size of the blur on the plate — a defocus of Δ spreads the light over about A·Δ/|dᵢ|. Focus lock reads 100% when the image plane sits on the target and 60% at the edge of the level’s tolerance, and magnification must land within 8%. Thin-lens, paraxial: no aberration, no thickness, no dispersion.

Game 17 · Optics learning guide

Turn the playthrough into a physics lesson.

Learning objectivePosition lenses or mirrors so a real image forms sharply at the required location and magnification.

01

What you will learn

  • Object distance, image distance, and focal length obey the imaging equation.
  • Magnification depends on the ratio of image and object distances.
  • A sharp real image forms only where the rays converge.

02

How to play

  1. Read the brief for image position, orientation, and size.
  2. Select and move the available lens or mirror along the optical bench.
  3. Check the ray diagram and refine the position until the sensor image is sharp.

03

Quick classroom check

What must be true about the emerging rays for a real image to form on a screen?

Suitable forUpper-secondary physics · lenses, mirrors, and image formation

Continue this topic

Move from play to explanation and exam-style practice.

Teachers can share the page link with a class. The game is free and does not require an account.