Crane Loader
Pull the crate off the deck and stop it in the berth — for the fewest joules.
Crane Loader berths
W = F d cos θ
700 N×4.4 m× cos30°
2,667J
friction Wf 1,638 Jrelease ΔK 1,030 J
How the physics works
- Simple definition
- Work is the energy a force transfers when its component along the motion acts through a displacement.
- Example
- Pulling a crate 5 m with 200 N of cable tension at 30° to the deck transfers 200 × 5 × cos 30° ≈ 866 J.
The cable pulls with a constant force F held at a constant angle θ, and the jib fixes the haul distance d, so the energy it transfers is exactly W = F d cos θ. Only the component along the deck does work; the vertical component does none, because the crate never rises.
That vertical component is not wasted, though. It carries part of the weight, so the deck only pushes back with N = mg − F sin θ and friction bills you Wf = μN d. Raising θ therefore buys a cheaper haul — right up until F sin θ reaches mg and the crate would lift clear of the deck, which the winch refuses.
Whatever survives the drag is kinetic energy at the moment the jib lets go: ΔK = W − Wf. The crate then coasts, losing μmg per metre, and stops after K / μmg. That is why a greased rail carries a small release energy such a long way.
Two berths add the rest of the chapter. A breaker trips when P = Win / t climbs over the winch ceiling, and a worn gearbox draws Win = W / η out of the charge for every joule that reaches the cable.