A positive point charge of 3.75 × 10⁻⁹ C creates an electric field. Calculate the field strength at a distance 6.8 × 10⁻² m and the force on a positive charged droplet of charge 1.9 × 10⁻⁹ C placed there.

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7.29 × 10³ N/C; 1.39 × 10⁻⁵ N away from the source E = kQ/r² = (8.99 × 10⁹ × 3.75 × 10⁻⁹) ÷ (6.8 × 10⁻²)². E = 7.29 × 10³ N/C, directed away from the positive source. Force F = qE. F = 1.9 × 10⁻⁹ × 7.29 × 10³ = 1.39 × 10⁻⁵ N away from the source.

Point-charge field acting on a charged droplet

A positive point charge of 3.75 × 10⁻⁹ C creates an electric field. Calculate the field strength at a distance 6.8 × 10⁻² m and the force on a positive charged droplet of charge 1.9 × 10⁻⁹ C placed there.

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