AP · AP 1 · free response
AP Physics 1: Algebra-Based · Question 10
AP Physics 1: Algebra-Based · Original GioPhysics question with a detailed, mark-by-mark answer guide.
- Demand
- discriminating
- Marks
- 11
- Topics
- 3
- Answer
- Complete
A solid sphere and a block have the same mass. Both are released from rest at the same height at the top of an incline. The sphere rolls down without slipping. The block slides down a frictionless section of the same incline. The moment of inertia of a solid sphere about its center is (2/5)MR².
- (a)
Indicate Indicate which object reaches the bottom of the incline with the greater translational speed, or whether they arrive with the same speed. No justification is required in this part.
1 mark - (b)
Derive Derive expressions for the translational speed of each object at the bottom of the incline, in terms of g and the height h.
4 marks - (c)
Justify Use your expressions to justify the answer you gave in part (a).
2 marks - (d)
Explain Explain, without using equations, why the sphere arrives more slowly, and explain why the answer does not depend on the mass or the radius of the sphere.
4 marks
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(a)
Indicate Indicate which object reaches the bottom of the incline with the greater translational speed, or whether they arrive with the same speed. No justification is required in this part.
Identify what the question is testing, organise the response into distinct mark-earning points, and make every conclusion traceable to a physical principle or to the evidence supplied.
- 1
1 point: the block
(b)
Derive Derive expressions for the translational speed of each object at the bottom of the incline, in terms of g and the height h.
List the given quantities with units, identify the required quantity, write the governing relationship before substituting, and keep extra digits until the final line so rounding does not distort the result.
- 1
1 point: block — Mgh = ½Mv², so v = √(2gh)
- 2
1 point: sphere — energy is shared between translation and rotation, Mgh = ½Mv² + ½Iω²
- 3
1 point: applies the rolling condition ω = v/R and substitutes I = (2/5)MR², giving Mgh = (7/10)Mv²
- 4
1 point: v = √(10gh/7)
(c)
Justify Use your expressions to justify the answer you gave in part (a).
List the given quantities with units, identify the required quantity, write the governing relationship before substituting, and keep extra digits until the final line so rounding does not distort the result.
- 1
1 point: compares the coefficients — 10/7 = 1.43 is smaller than 2, so the sphere's speed is smaller
- 2
1 point: states the ratio explicitly, v_sphere / v_block = √(5/7) = 0.85
(d)
Explain Explain, without using equations, why the sphere arrives more slowly, and explain why the answer does not depend on the mass or the radius of the sphere.
State the outcome first, then link cause to effect with the relevant physical principle. Each link in the reasoning should be explicit enough to earn its own marking point.
- 1
1 point: both objects convert the same gravitational potential energy per unit mass
- 2
1 point: the sphere must also spin as it moves, so part of that energy goes into rotational kinetic energy and less is left for translation
- 3
1 point: the mass appears in every energy term and cancels, so it cannot affect the result
- 4
1 point: the radius cancels because the rolling condition ties ω to v through the same R that appears in the moment of inertia — only the shape factor 2/5 survives
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