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AP · AP 2 · multiple choice

AP Physics 2: Algebra-Based · Question 5

AP Physics 2: Algebra-Based · Original GioPhysics question with a detailed, mark-by-mark answer guide.

Demand
demanding
Marks
1
Topics
1
Answer
Complete
Object placed 10 cm from a converging lens of focal length 15 cmconverging lensFFobject10 cmf = 15 cm
Figure 2A converging lens, drawn as a vertical line with outward-pointing arrowheads at each end, stands on a horizontal dashed principal axis. A focal point F is marked by a dot on the axis on each side of the lens, and the distance from the centre of the lens to the focal point on the far side is labelled f = 15 cm. A short upright arrow labelled "object" stands on the axis on the near side, and the distance from it to the centre of the lens is marked 10 cm, so the object lies between the focal point and the lens. No construction rays and no image are drawn.
multiple choice1 mark

An object is placed 10 cm in front of a converging lens of focal length 15 cm. Which describes the image?

  1. A

    real, inverted, and 30 cm from the lens

  2. B

    real, inverted, and 6.0 cm from the lens

  3. C

    virtual, upright, and 30 cm from the lens

  4. D

    virtual, upright, and 6.0 cm from the lens

Ready to self-mark?Reveal the detailed answer guide
Answer overviewCorrect answer: C — virtual, upright, and 30 cm from the lens
01

Answer and reasoning

1 mark
How to approach it

Predict from the governing principle before looking for a matching option. Then reject alternatives by checking direction, units, limiting behaviour or the physical meaning of each statement.

  1. 1

    The correct choice is C: virtual, upright, and 30 cm from the lens

  2. 2

    The object is inside the focal length, so the image must be virtual and upright — a candidate who checks that first can discard A and B without calculating. Solving 1/v = 1/15 − 1/10 gives v = −30 cm, and the negative sign is the confirmation, not an error.

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