A straight wire segment of length 0.19 m carries 2.8 A in a 0.33 T field. The angle between current and field is 47°. Find the magnetic-force magnitude.

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Final answer: 0.128 N For a straight current-carrying segment, the vector relation F = IL × B means that only the magnetic-field component perpendicular to the current produces force. The magnitude is therefore F = BIL sinθ = (0.33)(2.8)(0.19)sin(47°). Evaluating the trigonometric factor gives a magnetic-force magnitude of 0.128 N. Because sin(47°) is below one, 0.128 N is smaller than the perpendicular maximum BIL = 0.176 N; the force direction would be perpendicular to both current and field.

Current-carrying wire 4

A straight wire segment of length 0.19 m carries 2.8 A in a 0.33 T field. The angle between current and field is 47°. Find the magnetic-force magnitude.

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