IGCSE · 4 · structured
Electricity and magnetism · Question 9
Electricity and magnetism · Original GioPhysics question with a detailed, mark-by-mark answer guide.
- Demand
- routine
- Marks
- 8
- Topics
- 1
- Answer
- Complete
A household electric shower is connected to the 230 V mains supply through a fuse and an earth wire. The shower has a metal case and is marked 8.5 kW.
- (a)
Calculate Calculate the current in the shower when it is operating normally.
2 marks - (b)
Explain Explain how the earth wire and the fuse together protect a person who touches the metal case if a live wire comes loose inside the shower.
3 marks - (c)
Calculate The shower is used for a total of 30 minutes each day. Electrical energy costs 24 cents per kilowatt-hour. Calculate the cost of using the shower for 30 days.
3 marks
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(a)
Calculate Calculate the current in the shower when it is operating normally.
List the given quantities with units, identify the required quantity, write the governing relationship before substituting, and keep extra digits until the final line so rounding does not distort the result.
- 1
I = P / V = 8500 / 230
- 2
I = 37 A
(b)
Explain Explain how the earth wire and the fuse together protect a person who touches the metal case if a live wire comes loose inside the shower.
State the outcome first, then link cause to effect with the relevant physical principle. Each link in the reasoning should be explicit enough to earn its own marking point.
- 1
the earth wire connects the metal case to earth through a very low resistance path
- 2
if the live wire touches the case, a very large current flows to earth rather than through the person
- 3
this current melts the fuse, breaking the live wire and isolating the appliance
(c)
Calculate The shower is used for a total of 30 minutes each day. Electrical energy costs 24 cents per kilowatt-hour. Calculate the cost of using the shower for 30 days.
List the given quantities with units, identify the required quantity, write the governing relationship before substituting, and keep extra digits until the final line so rounding does not distort the result.
- 1
energy per day = 8.5 kW × 0.50 h = 4.25 kWh
- 2
energy in 30 days = 127.5 kWh
- 3
cost = 127.5 × 24 = 3060 cents = $30.60
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