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MYP Physics · 07 · data analysis

Estimating specific heat capacity

Thermal physics · Original GioPhysics question with a detailed, mark-by-mark answer guide.

Demand
demanding
Marks
8
Topics
2
Answer
Complete
data analysis8 marks

An insulated 0.50 kg metal block is heated electrically. A joulemeter measures energy supplied. The block begins at 20.0 °C.

Heating data for the metal block
Energy supplied / JTemperature / °C
020.0
200024.8
400029.6
600034.3
800039.1
  1. a

    Describe Describe the relationship between energy supplied and temperature rise.

    2 marks
  2. b

    Calculate Use the full data range to estimate the metal's specific heat capacity.

    3 marks
  3. c

    Evaluate The accepted value is 800 J kg⁻¹ K⁻¹. Explain one likely reason for the higher experimental value and propose a specific improvement.

    3 marks
Ready to self-mark?Reveal the detailed answer guide
Answer overviewKey answer: States that temperature rise is approximately directly proportional to energy supplied. Supports the claim with the near-constant increase of about 4.8 °C for each 2000 J. Finds temperature rise = 39.1 − 20.0 = 19.1 °C.
01

a

2 marks

Describe Describe the relationship between energy supplied and temperature rise.

How to approach it

Read the data before explaining it. Quote the relevant values or trend, show the comparison or calculation, and then connect that numerical evidence to the physical conclusion—including uncertainty or anomalies when they matter.

  1. 1

    States that temperature rise is approximately directly proportional to energy supplied.

  2. 2

    Supports the claim with the near-constant increase of about 4.8 °C for each 2000 J.

02

b

3 marks

Calculate Use the full data range to estimate the metal's specific heat capacity.

How to approach it

Read the data before explaining it. Quote the relevant values or trend, show the comparison or calculation, and then connect that numerical evidence to the physical conclusion—including uncertainty or anomalies when they matter.

  1. 1

    Finds temperature rise = 39.1 − 20.0 = 19.1 °C.

  2. 2

    Uses c = Q ÷ (mΔT).

  3. 3

    Obtains c = 8000 ÷ (0.50 × 19.1) ≈ 838 J kg⁻¹ K⁻¹.

03

c

3 marks

Evaluate The accepted value is 800 J kg⁻¹ K⁻¹. Explain one likely reason for the higher experimental value and propose a specific improvement.

How to approach it

Read the data before explaining it. Quote the relevant values or trend, show the comparison or calculation, and then connect that numerical evidence to the physical conclusion—including uncertainty or anomalies when they matter.

  1. 1

    Identifies a relevant effect such as energy heating the surroundings, heater, or temperature sensor rather than only the block.

  2. 2

    Explains that treating all supplied energy as block energy while the measured temperature rise is reduced makes Q ÷ (mΔT) overestimate c.

  3. 3

    Proposes a linked improvement such as better insulation and a lid, embedding the heater and probe well, or determining the apparatus heat capacity.

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