MYP Physics · Unit 07
Thermal physics
Temperature, internal energy, transfer mechanisms, specific heat, latent heat, gas behaviour, and thermal design.
- 21
- questions
- 19
- total marks
- 5
- mapped topics
Heating during a change of state
Pure ice at its melting temperature is heated steadily. Some ice melts, but the temperature remains constant. Which statement best explains the observation?
- A
No energy enters because the temperature is constant.
- B
Energy increases particle potential energy as the solid structure changes.
- C
The particles stop moving while melting.
- D
The energy is destroyed by the phase change.
- a
Select and explain Select the best explanation and distinguish internal energy from temperature.
3Ready to self-mark?Reveal the detailed answer
Mark-by-mark answer
Correct choiceB
Selects option B: melting increases particle potential energy while the structure changes.
Explains that energy is transferred into the ice even though temperature is constant.
Explains that the energy changes particle arrangement or potential energy rather than increasing average kinetic energy during melting.
Build deeper understandingReveal the teacher insight
Deeper learning cue
Use a particle sketch before and during melting so the plateau is not mistaken for a break in energy transfer.
Estimating specific heat capacity
An insulated 0.50 kg metal block is heated electrically. A joulemeter measures energy supplied. The block begins at 20.0 °C.
| Energy supplied / J | Temperature / °C |
|---|---|
| 0 | 20.0 |
| 2000 | 24.8 |
| 4000 | 29.6 |
| 6000 | 34.3 |
| 8000 | 39.1 |
- a
Describe Describe the relationship between energy supplied and temperature rise.
2Ready to self-mark?Reveal the detailed answer
Mark-by-mark answer
States that temperature rise is approximately directly proportional to energy supplied.
Supports the claim with the near-constant increase of about 4.8 °C for each 2000 J.
- b
Calculate Use the full data range to estimate the metal's specific heat capacity.
3Ready to self-mark?Reveal the detailed answer
Mark-by-mark answer
Finds temperature rise = 39.1 − 20.0 = 19.1 °C.
Uses c = Q ÷ (mΔT).
Obtains c = 8000 ÷ (0.50 × 19.1) ≈ 838 J kg⁻¹ K⁻¹.
- c
Evaluate The accepted value is 800 J kg⁻¹ K⁻¹. Explain one likely reason for the higher experimental value and propose a specific improvement.
3Ready to self-mark?Reveal the detailed answer
Mark-by-mark answer
Identifies a relevant effect such as energy heating the surroundings, heater, or temperature sensor rather than only the block.
Explains that treating all supplied energy as block energy while the measured temperature rise is reduced makes Q ÷ (mΔT) overestimate c.
Proposes a linked improvement such as better insulation and a lid, embedding the heater and probe well, or determining the apparatus heat capacity.
Build deeper understandingReveal the teacher insight
Deeper learning cue
Discuss that heat-loss effects can depend on the analysis method; reward a causal chain that matches the student's stated model.
Design a fair insulation comparison
A food-delivery team wants to compare felt, bubble wrap, and corrugated card as insulation around identical cups. Available equipment includes cups with lids, thermometers, measuring cylinders, a kettle, a stopwatch, elastic bands, and equal-thickness samples of each material.
- a
Formulate Write a focused research question and a testable hypothesis with scientific reasoning.
3Ready to self-mark?Reveal the detailed answer
Mark-by-mark answer
Writes a question linking insulation material to a measured temperature change over a fixed time.
States a directional, testable hypothesis identifying one material or material feature.
Justifies the hypothesis using conduction, trapped air, convection, and/or radiation appropriately.
- b
Design Describe a safe method that makes the comparison valid and produces sufficient data.
3Ready to self-mark?Reveal the detailed answer
Mark-by-mark answer
Controls water volume, starting temperature, cup and lid, insulation area and thickness, room conditions, and measurement duration.
Measures temperature at regular times for every material and an uninsulated control, with repeats or simultaneous trials.
Includes safe handling of hot water and a consistent method for mixing or positioning the thermometer.
- c
Process State how the data should be processed to decide which material is best.
2Ready to self-mark?Reveal the detailed answer
Mark-by-mark answer
Calculates mean temperature change or cooling rate for each material from repeated trials.
Compares results on the same temperature–time graph and considers spread or uncertainty before concluding.
Build deeper understandingReveal the teacher insight
Deeper learning cue
Equal thickness is not automatically equal mass or cost; those can become a second design criterion after the physics comparison.
More focused practice
Seven quick mastery questions
Open one task at a time, reveal the worked reasoning, then mark it mastered or save it to revisit.
Criterion A
Hot-chocolate energy
4 marks · routineOpen question →Criterion C
Identify the mystery liquid
6 marks · demandingOpen question →Criterion D
Why the metal spoon wins
5 marks · routineOpen question →Criterion A
Ice for the science picnic
5 marks · demandingOpen question →Criterion A
Bridge-gap reasoning
3 marks · recallOpen question →Criterion C
Cooling-curve checkpoint
6 marks · demandingOpen question →Criterion B
Lunch-box insulation trial
8 marks · discriminatingOpen question →Criterion C
A covered sample cools
8 marks · demandingOpen question →Criterion C
Cooling through a change of state
8 marks · demandingOpen question →Criterion C
A heater is switched off
8 marks · demandingOpen question →Criterion C
A changing room
8 marks · demandingOpen question →Criterion C
A cold pack warms
8 marks · demandingOpen question →Criterion C
A small block receives energy
8 marks · demandingOpen question →Criterion C
Opening the container
8 marks · demandingOpen question →Criterion C
A probe in an unstirred sample
8 marks · demandingOpen question →Criterion C
A slowly cooling cup
8 marks · demandingOpen question →Criterion C
A warming ice mixture
8 marks · demandingOpen question →Criterion C
Interpret a phase-change heating record
12 marks · discriminatingOpen question →Reference subsectionMapped lessons for this unit
Temperature and internal energy
Connect temperature, internal energy, and observable change without treating them as identical quantities.
Open lesson →Specific heat and latent heat
Criterion B prompt: choose a method that reduces unwanted transfer and explain remaining limitations.
Open lesson →Conduction, convection, and radiation
Compare mechanisms with evidence, then use the comparison to improve an insulating design.
Open lesson →Gas laws and absolute temperature
Criterion C focus: compare data while naming controlled variables and model conditions.
Open lesson →Thermal-data problem studio
Evaluate whether a calculated temperature or energy change is physically plausible in context.
Open lesson →