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Medical Physics · reward round

Echo Hunter

Echo Hunter

Level 1 — First interface: Soft tissue, 1540 m/s, one hidden interface. Read the echo time off the scope and call the depth with d = v t / 2.

Tap the stage to fire the first pulse

Fire an ultrasound pulse into a block of tissue and read the echoes it sends back. Each interface returns a spike at t = 2d/v, sized by the impedance mismatch α = (Z₂ − Z₁)²/(Z₁ + Z₂)² and faded by depth. Drag the depth gate until its ghost line lands on a peak, then call it. The block changes material as you climb the levels — so the same echo time stops meaning the same depth.

Score0best 0 · streak 0× · within 2 mm = +3
Depth gate64.0mmt = 2d/v = 83.1 µs at 1540 m/s
BlockSOFT TISSUEZ = 1.63 MRayl · interface 1/1 · level 1/5

Score 0 · level 1/5 · Soft tissue, 1540 m/s, one hidden interface. Read the echo time off the scope and call the depth with d = v t / 2.

How the physics works

Ultrasound imaging is one equation used twice. The machine knows the time t at which an echo came back and the speed v of sound in the material, so the interface that made it sits at d = v t / 2 — the halving is there because the pulse made the trip twice. While the gate falls down the block it is showing exactly that: at scope time t the gate is at depth v t / 2, and a spike appears the instant the gate reaches something.

How big that spike is comes from acoustic impedance, Z = ρ c. At a boundary between materials the fraction of intensity sent back is α = (Z₂ − Z₁)²/(Z₁ + Z₂)², which is about 1% for a fat–soft-tissue boundary and about 43% for soft tissue against bone. The scope plots pressure amplitude rather than intensity, so the heights go as √α, then fade with depth: the beam is absorbed on the way down and on the way back, and the time-gain compensation in this machine leaves 0.5 dB/cm uncorrected. That is why the same interface returns a visibly shorter spike the deeper it sits — and why nearly all the sound is lost at a gas pocket, where α ≈ 1 and everything behind it goes dark.

The later levels change what the block is made of, and that is the whole point. Fat carries sound at 1450 m/s and cortical bone at 4080, so an echo at 90 µs is 65 mm deep in fat and 184 mm deep in bone. Real scanners assume 1540 m/s everywhere and are therefore quietly wrong wherever the tissue is not average — a known source of measurement error that sonographers correct for by hand. The width of the transmit pulse sets the other limit you meet here: two interfaces closer together than about half a pulse length merge into one bump, which is axial resolution, and the only cure is a shorter, higher-frequency pulse that in turn cannot travel as deep.

Game 29 · Medical Physics learning guide

Turn the playthrough into a physics lesson.

Learning objectiveUse pulse travel time and echo strength to locate hidden tissue boundaries in a simplified ultrasound scan.

01

What you will learn

  • Pulse-echo depth is calculated from d = vt/2.
  • The factor of two accounts for the outward and return journeys.
  • Acoustic-impedance changes determine reflected echo strength.

02

How to play

  1. Fire a pulse and inspect the arrival times and heights of the A-scan echoes.
  2. Move the depth gate to the boundary predicted from d = vt/2.
  3. Lock the call, then adapt when a later level changes the sound speed or tissue interfaces.

03

Quick classroom check

Why must the measured pulse travel time be divided by two when calculating tissue depth?

Suitable forUpper-secondary physics · ultrasound and medical imaging

Continue this topic

Move from play to explanation and exam-style practice.

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