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MYP Physics · Unit 08

Pressure and fluids

Pressure in solids, liquids, and gases, atmospheric measurement, buoyancy, hydraulics, and fluid evidence.

21
questions
18
total marks
5
mapped topics
01
Criterion AYears 1–2multiple choicerecall

Snowshoes and pressure

3 marks

A hiker stands still on soft snow. Why do wide snowshoes reduce how far the hiker sinks?

  1. A

    They reduce the hiker's weight.

  2. B

    They increase the force on the snow.

  3. C

    They spread the same force over a larger area, reducing pressure.

  4. D

    They make the snow denser.

  1. a

    Select and explain Select the correct explanation and connect it to the pressure equation.

    3
    Ready to self-mark?Reveal the detailed answer3 marks

    Mark-by-mark answer

    Correct choiceC

    1. Selects option C: the same force spread over a larger area produces lower pressure.

    2. States pressure = force ÷ area.

    3. Explains that weight is essentially unchanged while larger contact area produces lower pressure.

Build deeper understandingReveal the teacher insight

Deeper learning cue

Compare one shoe, two shoes, and kneeling on a board to separate contact area from total weight.

02
Criterion CYears 2–4data analysisroutine

Pressure below an unknown liquid

7 marks

A pressure sensor measures gauge pressure below the surface of a liquid. Gauge pressure excludes atmospheric pressure. Use g = 10 N kg⁻¹.

Gauge pressure at different depths
Depth / mGauge pressure / Pa
0.05400
0.10800
0.151200
0.201600
  1. a

    Describe Describe the pattern supported by the data.

    2
    Ready to self-mark?Reveal the detailed answer2 marks

    Mark-by-mark answer

    1. States that gauge pressure is directly proportional to depth.

    2. Supports the statement, for example by noting that doubling depth doubles pressure.

  2. b

    Determine Use p = ρgh to determine the liquid's density.

    3
    Ready to self-mark?Reveal the detailed answer3 marks

    Mark-by-mark answer

    1. Rearranges to ρ = p ÷ (gh).

    2. Substitutes a consistent pair, for example 1600 ÷ (10 × 0.20).

    3. Obtains density = 800 kg m⁻³.

  3. c

    Predict Predict the gauge pressure at a depth of 0.35 m and state one model assumption.

    2
    Ready to self-mark?Reveal the detailed answer2 marks

    Mark-by-mark answer

    1. Calculates p = 800 × 10 × 0.35 = 2800 Pa.

    2. States a relevant assumption such as constant liquid density, uniform gravitational field, or a stationary connected liquid.

Build deeper understandingReveal the teacher insight

Deeper learning cue

Make the zero-pressure reference explicit so students do not add atmospheric pressure when the question asks for gauge pressure.

03
Criterion DYears 4–5extended responsediscriminating

Reserve buoyancy for a rescue platform

8 marks

A sealed rescue platform has external volume 0.60 m³ and mass 120 kg. It operates in fresh water of density 1000 kg m⁻³. Designers require no more than 80% of its volume to be submerged in calm water, leaving reserve buoyancy. Each person is represented by a mass of 65 kg.

  1. a

    Determine Determine the maximum total supported mass at the 80% submergence limit.

    3
    Ready to self-mark?Reveal the detailed answer3 marks

    Mark-by-mark answer

    1. Calculates displaced volume at the limit = 0.80 × 0.60 = 0.48 m³.

    2. Uses floating equilibrium so supported mass equals displaced-water mass.

    3. Obtains maximum total mass = 1000 × 0.48 = 480 kg.

  2. b

    Calculate Calculate the maximum whole number of represented people that can board without exceeding the design limit.

    2
    Ready to self-mark?Reveal the detailed answer2 marks

    Mark-by-mark answer

    1. Finds available payload mass = 480 − 120 = 360 kg.

    2. Calculates 360 ÷ 65 = 5.54 and therefore limits the platform to 5 whole people under this model.

  3. c

    Evaluate Evaluate whether advertising a five-person capacity is justified from this calculation alone.

    3
    Ready to self-mark?Reveal the detailed answer3 marks

    Mark-by-mark answer

    1. Recognises that the calculation uses a simplified fixed person mass and calm fresh water.

    2. Identifies a relevant real condition such as equipment mass, waves, uneven loading, leakage, dynamic boarding, or water density.

    3. Recommends safety-factor testing or a lower rated capacity until stability and worst-case loading are verified.

Build deeper understandingReveal the teacher insight

Deeper learning cue

This separates basic flotation from safe design: enough upthrust is necessary, but stability and dynamic conditions also matter.

More focused practice

Seven quick mastery questions

Open one task at a time, reveal the worked reasoning, then mark it mastered or save it to revisit.

12

Criterion A

A box moved to a mountain reservoir

6 marks · demandingOpen question →
17

Criterion A

A pod with regulated internal pressure

6 marks · demandingOpen question →
18

Criterion D

Evaluate a community flood-barrier design

16 marks · discriminatingOpen question →
Reference subsectionMapped lessons for this unit
MYP-08.01

Pressure in solid contact

Investigate how force and area change pressure, then apply the result to a local design problem.

Open lesson →
MYP-08.02

Pressure with depth in fluids

Use depth, density, and gravitational field strength to explain fluid-pressure patterns.

Open lesson →
MYP-08.03

Atmospheric pressure and manometers

Criterion C focus: interpret a pressure difference from a fluid-column measurement.

Open lesson →
MYP-08.04

Buoyancy and Archimedes' principle

Connect displaced fluid to upthrust and test a floating or sinking prediction.

Open lesson →
MYP-08.05

Fluid-pressure problem studio

Apply a pressure model, check units and scale, and state where the model may fail.

Open lesson →