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Optional unit · institution-dependent · Interactive lesson

Optical Bloch equations for a driven, damped two-level atom

These three equations sit under every Doppler-cooling estimate, every two-level saturation lineshape and, in another notation, every pulse applied to an uncoupled nuclear spin. Here they are derived, not posited: switch a laser on in the atom's vacuum master equation and T₁, T₂, the ceiling on scattering and the power-broadened width all follow from Γ and Ω.

UAQM-14.06 · Lesson 6 of 9 in this unit. Position is not a completion score.
Starting model: Optical Bloch equations for a driven, damped two-level atomSteady-state excited population of a driven two-level atom against detuning δ from −8Γ to +8Γ, at Rabi frequency 1.0 Γ and pure dephasing 0.0 Γ. The solid curve is the optical Bloch result, peaking at 0.333; the dashed curve has the same peak and the weak-drive width 2/T₂, the dashed horizontal line is the ceiling 1/2, and the dot marks δ = 3.0 Γ.solid: steady state at Ω = 1.0 Γdashed: same peak, width 2/T₂FWHM 1.73 Γ, T₂ = 2.00 T₁ceiling 1/2ρₑₑFWHM−8 Γδ = 0+8 Γ
Start with a picture. Change the model in the lab below.

Optional unit · institution-dependent. Units 14 and 15 are the course’s optional extension into open systems and quantum gases. Unit 14 builds on radiation and decay; Unit 15 builds on second quantisation. Keep the fifteen-unit numbering and follow your institution’s required syllabus. Optional work is not a required completion gate.

1

Build the model

The drive pumps, the vacuum drains, and the steady state never passes one half.

The key idea

The optical Bloch equations are three linear equations for the Bloch vector of a two-level atom driven by a near-resonant classical field and damped by spontaneous emission, written in the frame that rotates with the field.

Example. A rubidium-87 atom on its 780 nm cycling line, with Γ = 3.812 × 10⁷ s⁻¹, driven on resonance at Ω = Γ settles at ρₑₑ = (Γ²/4)/(3Γ²/4) = 1/3 and scatters Γ/3 = 1.27 × 10⁷ photons per second.

The complete physical model and assumptions

The optical Bloch equations are what topic 14.03's master equation becomes once a laser is switched on. Put the classical drive (ħΩ/2)σₓ and the detuning term −(ħδ/2)σz into the Hamiltonian in Quantum Mechanics II's rotating frame, keep the vacuum dissipator as it was, and the expectation values u, v and w of the three Pauli matrices obey three real, linear equations: the Bloch vector precesses about the axis (Ω, 0, −δ) while its transverse part shrinks at Γ/2 and its inversion relaxes towards the ground state at Γ. That single jump operator fixes T₁ = 1/Γ and T₂ = 2/Γ, so the coherence outlives the population by exactly a factor of two, and any further dephasing can only shorten T₂. Setting the time derivatives to zero solves the model. A weak drive raises the excited population as Ω², reproducing the golden-rule Lorentzian; a strong one saturates it towards 1/2, because the field stimulates emission exactly as hard as it drives absorption. The atom then scatters at most Γ/2 photons per second, and because the peak saturates while the wings keep growing, the line widens to Γ√(1 + 2Ω²/Γ²). The equations stop where their inputs do: a classical field, the rotating-wave approximation with Ω and |δ| far below ω₀, a Markovian vacuum the drive does not alter, two levels, an atom at rest, and no cavity coupling strong enough to make the quantum state of the field matter.

1Put the laser in the Hamiltonian, keep the vacuum's dissipator

Units are SI, with Ω, δ and Γ angular frequencies in s⁻¹ (divide by 2π to compare with spectra in MHz); no metric signature enters, because the atom is non-relativistic and the laser is a classical field. Take a ground state |g⟩ and an excited state |e⟩ split by ħω₀, in the field E₀ε̂ cos(ωL t). In the frame rotating at ωL, with the terms at 2ωL dropped, Quantum Mechanics II's rotating-wave approximation (quoted) leaves H = −(ħδ/2)σz + (ħΩ/2)σₓ, with δ = ωL − ω₀ and the field's phase chosen so that Ω is real and positive. Topic 14.03 derived the vacuum's term Γ(σ₋ρσ₊ − ½σ₊σ₋ρ − ½ρσ₊σ₋) for an undriven atom, and it is kept unchanged. The frame change cannot alter it, because the rotating phases that σ₋ and σ₊ acquire are opposite and cancel in every product. Keeping it is an approximation with a size: the drive splits the dressed atom by about Ω, while the vacuum's coupling varies only on the scale ω₀. For rubidium's 780 nm line at Ω = Γ that ratio is 1.6 × 10⁻⁸.

2Take expectation values: precession plus relaxation

For any operator A the master equation gives d⟨A⟩/dt = (i/ħ)⟨[H, A]⟩ + Γ⟨σ₊Aσ₋ − ½σ₊σ₋A − ½Aσ₊σ₋⟩. Apply it to the Pauli matrices, with u = ⟨σₓ⟩, v = ⟨σy⟩ and w = ⟨σz⟩. H is (ħ/2)(Ωσₓ − δσz), and [σᵢ, σⱼ] = 2iεᵢⱼₖσₖ turns its part into the precession dr/dt = a × r of a spin in a field, with r = (u, v, w) and a = (Ω, 0, −δ). In the dissipator, σ₋σ₋ = 0 and σ₋σ₊σ₋ = σ₋ give dσ₋/dt = −(Γ/2)σ₋, while σ₊σzσ₋ = −σ₊σ₋ gives dσz/dt = −Γ(1 + σz). Together, derived: du/dt = δv − Γu/2, dv/dt = −δu − Ωw − Γv/2, dw/dt = Ωv − Γ(w + 1). Each term is a rate times a dimensionless component, so the dimensions agree. Two limits check them. With Γ = 0 and δ = 0, starting from the ground state, w = −cos Ωt and v = sin Ωt: Quantum Mechanics II's lossless Rabi flopping. With Ω = 0 the population decays as e(−Γt) and the coherence as e(−Γt/2), Unit 12's Weisskopf-Wigner amplitudes.

3Two relaxation times from one jump operator

The inversion relaxes at Γ and the transverse components at Γ/2, which defines T₁ = 1/Γ and T₂ = 2/Γ. The factor of two is derived, not fitted: the excited amplitude decays as e(−Γt/2), the coherence is linear in it and the population quadratic. An environment that randomises the phase without causing transitions, a σz jump operator at rate γφ/2 as in topic 14.02's phase damping (quoted), adds γφ to the transverse rate only, so 1/T₂ = 1/(2T₁) + γφ and T₂ can only fall below 2T₁. With Γ/2 → 1/T₂ and Γ → 1/T₁ these are Felix Bloch's 1946 equations for nuclear magnetisation, quoted, with T₁ and T₂ as measured parameters; in NMR the reservoir is thermal, and topic 14.04's w → −1/(2n̄ + 1) replaces −1, an equilibrium polarisation of only 3.2 × 10⁻⁵ for protons at 9.4 T and 298 K. Measurements respect the bound: water protons have T₂ ≈ T₁ of a few seconds, tissue protons typically T₂ ≈ T₁/10, and an isolated rubidium atom's weak-probe line is Γ = 2π × 6.07 MHz wide, as its 26.23 ns lifetime predicts. A weak probe measures 2/T₂, so that is T₂ = 2T₁.

4Solve for the steady state

Set the derivatives to zero. The first equation gives u = 2δv/Γ, the third v = Γ(w + 1)/Ω, and the second then fixes w. With D = 4δ² + Γ² + 2Ω², derived: u = 4δΩ/D, v = 2ΓΩ/D, w = −(4δ² + Γ²)/D, and ρₑₑ = (1 + w)/2 = (Ω²/4)/(δ² + Γ²/4 + Ω²/2). Every term of D is a rate squared, so ρₑₑ is dimensionless. The third equation is also an energy balance: Ωv/2 = Γρₑₑ, photons taken from the laser per second equal photons scattered. For a weak drive ρₑₑ → (Ω²/4)/(δ² + Γ²/4), and R = Γρₑₑ becomes (πΩ²/2)L(δ), with L a normalised Lorentzian of full width Γ: Quantum Mechanics II's golden-rule rate, the weak-field limit. The steady state is mixed, |r|² = 1 − 4Ω⁴/D²; at Ω = Γ on resonance (u, v, w) = (0, 2/3, −1/3) and |r| = 0.745. It is reached through damped Rabi oscillations: on resonance the v-w block has eigenvalues −3Γ/4 ± i√(Ω² − Γ²/16), so once Ω exceeds Γ/4 the transient oscillates at √(Ω² − Γ²/16) and dies away at 3Γ/4.

5Saturation caps the rate at Γ/2 and widens the line

Raise Ω at fixed δ and ρₑₑ climbs towards 1/2, never past it. The field that drives |g⟩ → |e⟩ drives |e⟩ → |g⟩ by stimulated emission at the same rate, so a strong drive can only equalise the populations, and the Bloch vector shrinks to the centre of the ball. The scattering rate R = Γρₑₑ is capped at Γ/2. For rubidium-87, whose measured 26.23 ns lifetime gives Γ = 3.812 × 10⁷ s⁻¹, that is 1.91 × 10⁷ photons per second, a radiation-pressure force of at most ħkΓ/2 = 1.62 × 10⁻²⁰ N and a deceleration of 1.12 × 10⁵ m s⁻². Write s₀ = 2Ω²/Γ²; then ρₑₑ = (s₀/2)/(1 + s₀ + 4δ²/Γ²), half the peak falls at 4δ² = Γ²(1 + s₀), and the full width is Γ√(1 + s₀), derived. With ħΩ = dE₀, I = ½cε₀E₀² and Unit 12's Γ = ω₀³d²/(3πε₀ħc³), quoted, s₀ = I/Iₛₐₜ with Iₛₐₜ = πhcΓ/(3λ³) = 16.7 W m⁻² for rubidium. At low intensity the same numbers give the resonant cross-section ħω₀Γ/(2Iₛₐₜ) = 3λ²/(2π) = 2.91 × 10⁻¹³ m², the one absorption imaging uses to count cold rubidium atoms.

6Where the optical Bloch equations stop

Each input has a limit with a number on it. The rotating-wave approximation drops counter-rotating terms that shift the line by the Bloch-Siegert amount Ω²/(4ω₀), quoted: 4 × 10⁻⁹ Γ for rubidium at Ω = Γ, but many linewidths for a superconducting qubit driven at Ω/ω₀ of a per cent or more. The Markov step needs Ω and Γ far below the inverse of the vacuum's correlation time, which is of order ω₀. Two levels need the others far away, which is why experiments use a closed cycling transition and circular polarisation. A moving atom sees δ − k⋅v, so the Doppler spread of a room-temperature rubidium vapour, 0.51 GHz, is inhomogeneous broadening: the formula averaged over velocities, not a shorter T₂. And the field must be classical. In a cavity whose coupling g beats both its loss and Γ, the photon number of the mode matters, the vacuum Rabi splitting appears, and Unit 11's Jaynes-Cummings dynamics replaces these equations. The steady state also leaves something out: the spectrum and photon statistics of the scattered light need the quantum regression theorem, quoted in topic 14.07.

2

Key equations

Read the units, assumptions and limits before substituting.

Driven atom in the rotating frame

H = −(ħδ/2)σz + (ħΩ/2)σₓ, δ = ωL − ω₀

Quoted from Quantum Mechanics II: in the frame rotating at ωL, with the 2ωL terms dropped, the oscillating drive becomes a fixed field.

Ω the Rabi frequency, ħΩ = |⟨e|d⋅ε̂|g⟩|E₀, and δ the detuning, both in s⁻¹; E₀ in V m⁻¹; H in J

Optical Bloch equations

du/dt = δv − Γu/2, dv/dt = −δu − Ωw − Γv/2, dw/dt = Ωv − Γ(w + 1)

Derived from topic 14.03's master equation with this H: precession about (Ω, 0, −δ), transverse decay at Γ/2, and w relaxing at Γ to −1.

u = ⟨σₓ⟩, v = ⟨σy⟩, w = ⟨σz⟩ = 2ρₑₑ − 1, all dimensionless; Γ, Ω and δ in s⁻¹

Longitudinal and transverse relaxation times

1/T₁ = Γ, 1/T₂ = Γ/2 + γφ, so T₂ ≤ 2T₁

One jump operator σ₋ drains the population at Γ and the amplitude at Γ/2, so radiative damping alone gives T₂ = 2T₁. Dephasing only shortens T₂.

T₁ and T₂ in s; γφ a pure-dephasing rate in s⁻¹, from a σz jump operator as in topic 14.02's phase damping

Steady-state excited population

ρₑₑ = (Ω²/4)/(δ² + Γ²/4 + Ω²/2)

Derived by setting the three derivatives to zero. It grows as Ω² for a weak drive and tends to 1/2 for a strong one, so R never exceeds Γ/2.

dimensionless; δ, Γ and Ω in s⁻¹; the photon scattering rate is R = Γρₑₑ, in s⁻¹

Power-broadened linewidth

ΔωFWHM = Γ√(1 + s₀), s₀ = 2Ω²/Γ²

Derived: the peak saturates while the wings still grow as Ω²/(4δ²), so the half-maximum points move out. At s₀ = 10 the line is 3.32Γ wide.

ΔωFWHM and Γ in s⁻¹, divided by 2π for Hz; s₀ the dimensionless saturation parameter on resonance

Saturation intensity of a cycling transition

Iₛₐₜ = πhcΓ/(3λ³), with s₀ = I/Iₛₐₜ

From ħΩ = dE₀, I = ½cε₀E₀² and Unit 12's Γ = ω₀³d²/(3πε₀ħc³). Rubidium's 780 nm line gives 16.7 W m⁻², or 1.67 mW cm⁻².

I and Iₛₐₜ in W m⁻²; h in J s; c in m s⁻¹; Γ in s⁻¹; λ the transition wavelength in m
3

Interactive lab

Predict first. Explore the model. Compare the result.

Explore the model

1.0 Γ
0.2 to 4 Γ; steps of 0.1.
0.0 Γ
0 to 1.5 Γ; steps of 0.1.
3.0 Γ
−8 to 8 Γ; steps of 0.5.

Try this. Park the marker at δ = 3Γ and raise Ω from 1Γ to 4Γ: the peak only climbs from 0.333 to 0.485, while the population at the marker grows ninefold, from 0.026 to 0.232. That is power broadening. Then add dephasing and watch T₂ fall below 2T₁.

Live results

PEAK EXCITED POPULATION
0.333
FULL WIDTH AT HALF MAXIMUM
1.73 Γ
SATURATION PARAMETER
2.00
SCATTERING RATE AT MARKER
0.026 Γ

Results follow this lesson’s model and assumptions. Displayed values are rounded.

Interactive Advanced Quantum Mechanics modelSteady-state excited population of a driven two-level atom against detuning δ from −8Γ to +8Γ, at Rabi frequency 1.0 Γ and pure dephasing 0.0 Γ. The solid curve is the optical Bloch result, peaking at 0.333; the dashed curve has the same peak and the weak-drive width 2/T₂, the dashed horizontal line is the ceiling 1/2, and the dot marks δ = 3.0 Γ.solid: steady state at Ω = 1.0 Γdashed: same peak, width 2/T₂FWHM 1.73 Γ, T₂ = 2.00 T₁ceiling 1/2ρₑₑFWHM−8 Γδ = 0+8 Γ
Steady-state excited population of a driven two-level atom against detuning δ from −8Γ to +8Γ, at Rabi frequency 1.0 Γ and pure dephasing 0.0 Γ. The solid curve is the optical Bloch result, peaking at 0.333; the dashed curve has the same peak and the weak-drive width 2/T₂, the dashed horizontal line is the ceiling 1/2, and the dot marks δ = 3.0 Γ.

Predict → change one variable → check

Plan a change before running it. Every other input stays at the saved baseline.

Saved baseline. Rabi frequency Ω: 1.0 Γ; Pure dephasing rate γφ: 0.0 Γ; Marker detuning δ: 3.0 Γ

Baseline 1.0; choose 0.2 to 4, in steps of 0.1.
4. Compared with the saved baseline, this result will…

This experiment is kept only while this page is open. It does not change saved course progress.

4

Catch the common trap

Driving harder does not push the atom up: in steady state no more than half the population is ever excited, however intense the laser. The error is carried over from Quantum Mechanics II's Rabi problem, where a π pulse inverts the atom completely, and students conclude that a strong enough continuous drive holds it inverted. A π pulse is a transient. It works when π/Ω is short against T₁ and is followed by free decay; with the drive left on, the oscillations of w damp, at 3Γ/4 on resonance, and settle at ρₑₑ = (Ω²/4)/(δ² + Γ²/4 + Ω²/2), below 1/2, because the same field that drives absorption drives stimulated emission equally hard. The ceiling belongs to two levels, not to strong fields: a laser medium reaches inversion by pumping through a third level that the pump does not couple back.

5

Practice & worked examples

3 authored examples. Make an attempt, then reveal the reasoning one step at a time.

EasyExample 1

A rubidium-87 atom at rest, with Γ = 3.812 × 10⁷ s⁻¹ on its 780 nm cycling transition, is driven at Ω = Γ by a laser tuned one linewidth below resonance, δ = −Γ. Find the steady-state Bloch vector, the excited population and the scattering rate, and check them against the energy balance and the resonant case.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

MediumExample 2

A 1.00 mW laser beam with a flat-top profile 5.00 mm across drives rubidium-87 atoms on their 780.24 nm cycling transition, Γ = 3.812 × 10⁷ s⁻¹. Find the saturation intensity, the saturation parameter and the Rabi frequency, the excited population and scattering rate on resonance, and the full width of the line in MHz.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

HardExample 3

A self-assembled quantum dot acts as a two-level emitter. Time-resolved fluorescence gives T₁ = 0.80 ns, and a weak resonant probe gives a Lorentzian of full width 1.30 μeV. Find T₂ and the pure-dephasing rate γφ, then the Rabi energy ħΩ at which power broadening doubles the line, with the peak excited population there. Compare a dot with the same T₁ and no pure dephasing.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

6

Quick check

Select an answer and explain it before checking.

A two-level atom with Γ/2π = 6.0 MHz is driven on resonance at saturation parameter s₀ = 2Ω²/Γ² = 1. The laser intensity is then raised ninefold, to s₀ = 9. What happens to the photon scattering rate and to the full width of the absorption line?
7

Review & continue

The optical Bloch equations are three linear equations for the Bloch vector of a two-level atom driven by a near-resonant classical field and damped by spontaneous emission, written in the frame that rotates with the field.

  • Explain the relationship without looking at the equation.
  • Check a sign, a unit and a model assumption in your working.
  • Return to the lab or worked example if a step is still unclear.

Extra challenging questions

Connect several ideas, explore supplied data, and compare your reasoning with a worked solution.