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Bounded modern-physics survey · Interactive lesson

Absorbed dose, equivalent dose, and shielding

Dose is where nuclear physics meets a person, and radiation protection runs on three numbers built from it. This topic computes them from a source's activity and the tissues it reaches, sizes the two levers, distance and shielding, before anyone enters the room, and is honest about what the final figure cannot say about any one body.

UPIII-11.06 · Lesson 6 of 9 in this unit. Position is not a completion score.
Starting model: Absorbed dose, equivalent dose, and shieldingLog-log plot of the gamma dose rate from a 1.0 GBq caesium-137 point source against distance r. The dashed line is the bare source, falling as 1/r²; the solid line lies 5.5 mm of lead lower, a narrow-beam factor e^(−μd) = 0.500. At r = 1.00 m the marker reads 42.01 µSv h⁻¹; the faint line is natural background, 0.27 µSv h⁻¹.dose rate, µSv h⁻¹10³100.10.25 m1 m4 mdashed: no shieldsolid: 5.5 mm lead = 1.0 x₁/₂background 0.27 µSv h⁻¹at r = 1.00 m: 42.01 µSv h⁻¹, 153.3 × background
Start with a picture. Change the model in the lab below.

Bounded modern-physics survey. This modern-physics material is an introductory survey, not a complete course in relativity, quantum, atomic, nuclear or particle physics. Your university determines the required depth and assessment.

1

Build the model

A gray counts joules per kilogram; the sievert layers judgement on top.

The key idea

Absorbed dose is the energy ionising radiation deposits per kilogram of matter, measured in grays (1 Gy = 1 J kg⁻¹); equivalent and effective dose, in sieverts, weight it for radiation type and for the tissues exposed.

Example. A 70 kg body absorbing 0.14 J uniformly from gamma rays receives D = 0.14 J ÷ 70 kg = 2.0 mGy; with wR = 1 for photons its effective dose is 2.0 mSv, about ten months of average natural background.

The complete physical model and assumptions

Ionising radiation harms tissue by depositing energy, so the first quantity is an energy ledger: absorbed dose, the mean energy imparted per unit mass, measured in grays, 1 Gy = 1 J kg⁻¹. Thermally the ledger is tiny, since a lethal 5 Gy warms water by about a millikelvin; it matters because the energy arrives in ionisations of roughly 30 eV each, strung along particle tracks through DNA. Their density along the track is why a gray of alpha particles does more harm than a gray of gamma rays, and radiation protection encodes it in two rounded weightings: wR turns absorbed dose into equivalent dose in sieverts, and normalised tissue factors wT sum organ doses into one effective dose, comparable with the world-average 2.4 mSv a year from natural background. The geometry is ordinary physics. Photons from a point source spread over 4πr², so dose rate falls as 1/r²; a slab removes a fixed fraction per unit thickness, so transmission is e(−μx) and each half-value thickness ln 2/μ halves it. The model stops in three places. Exponential attenuation is a narrow-beam result that scattered photons and finite-range charged particles both break; the weighting factors are protection conventions for stochastic risk at low dose, not measured physics; and a dose is the mass average of a random deposit, so it fixes an expected risk across a population, never one person's outcome.

1A gray is an energy ledger, and a small one

Absorbed dose is D = dε̄/dm: the mean energy imparted by ionising radiation to a small element of matter, divided by its mass. Its unit, the gray, is 1 J kg⁻¹, and a dose always belongs to a material, because air, water and bone absorb the same beam differently. By thermal standards the energies are minute. A whole-body dose of about 5 Gy, fatal to roughly half of those exposed without treatment, deposits 5 J in each kilogram and warms water by 5 ÷ 4186 = 1.2 × 10⁻³ K. The harm is not heat. Radiation spends its energy in ionisations of roughly 30 eV each, over a thousand times kT at body temperature and several times the few electronvolts that hold a chemical bond, strung along the tracks of charged particles. One gray puts about 5.6 × 10⁴ of them into a cell nucleus 8 µm across. The gray counts the joules; the biology depends on where they land.

2Radiation weighting: equal grays, unequal sieverts

A 5 MeV alpha particle loses energy in tissue at around 100 keV µm⁻¹; the electrons set moving by cobalt-60 gamma rays lose about 0.3 keV µm⁻¹. At the same absorbed dose, the alpha energy is packed into a few dense tracks that break DNA in clusters that cells repair badly, so a gray of alpha particles does more harm. Protection practice folds this into a radiation weighting factor, HT = wR DT, summed over the radiations present, with wR = 1 for photons, electrons and muons, 2 for protons, 20 for α particles and heavy ions, and a smooth function of energy for neutrons, from 2.5 for thermal neutrons to about 20 near 1 MeV. The result is the equivalent dose, in sieverts. The sievert has the gray's dimensions, J kg⁻¹, yet no instrument measures an equivalent dose: survey meters and badges read operational estimates calibrated in sieverts, while the quantity itself is an absorbed dose multiplied by a rounded convention chosen from low-dose biological effectiveness. So 2.0 mGy of alpha particles to the lung is 40 mSv to the lung, while 2.0 mGy of gamma rays is 2.0 mSv.

3Effective dose puts every exposure on one scale

Few exposures are uniform: a dental radiograph irradiates the jaw, inhaled radon progeny the airways. The effective dose E = ΣT wT HT weights each tissue's equivalent dose by its share of the total stochastic detriment: 0.12 for red marrow, colon, lung, stomach, breast and a remainder group; 0.08 for the gonads; 0.04 each for bladder, oesophagus, liver and thyroid; 0.01 each for bone surface, brain, salivary glands and skin. The weights sum to 1 like a probability distribution, and that normalisation is the point: if every tissue receives H, then E = H. So 20 mSv to the lung alone gives E = 0.12 × 20 mSv = 2.4 mSv, nominally as risky as 2.4 mSv spread over the whole body, and one year of world-average natural background. That background, about half of it from radon, is the baseline every other figure is read against: a chest radiograph, about 0.02 mSv, is three days of it; an abdominal CT scan, about 10 mSv, is four years.

4From activity to dose rate: the inverse square

For a small gamma source, energy conservation does the work. A source of activity A emitting y photons of energy Eγ per decay sends y A Eγ joules per second through every sphere drawn around it, so at distance r the energy fluence rate is y A Eγ/(4π r²). Tissue retains a fraction μₑₙ/ρ of it per unit areal density, so Ḋ = y A Eγ (μₑₙ/ρ)/(4π r²). For caesium-137, y = 0.851, Eγ = 662 keV and μₑₙ/ρ = 3.26 × 10⁻³ m² kg⁻¹ give 84 µGy h⁻¹ at 1 m for each GBq. Doubling the distance quarters the rate; stepping back by a factor of √2 halves it. The law fails close to an extended source, whose size is then comparable with r (near the middle of a long line source the rate falls only as 1/r), and it cannot see radiation scattered back by walls, floor and air. Alpha and beta emitters are a different case: their particles have finite ranges, a few centimetres of air for alphas and up to several metres for betas, or about 40 µm and a few millimetres of tissue, so distance protects against them abruptly, not as a power law.

5Shielding: constant chance per length gives an exponential

A photon crossing a slab has the same probability μ dx of interacting in each thin layer dx, however far it has already travelled. For N photons in a narrow beam that gives dN/dx = −μN, so N(x) = N₀ e(−μx): each photon crosses uncollided with probability e(−μx), and its mean free path is 1/μ. Each half-value thickness x₁/₂ = ln 2/μ halves the beam. For 662 keV photons in lead μ ≈ 1.26 cm⁻¹, so x₁/₂ ≈ 5.5 mm, and 25 mm of lead, about 4.5 half-value thicknesses, transmits e(−3.15) = 4.3%; water, with μ ≈ 0.086 cm⁻¹, needs 8.1 cm per halving. The narrow-beam law is optimistic for a real shield. Compton-scattered photons leave the pencil beam yet can still reach you, so a broad beam transmits B e(−μx), with a buildup factor B ≥ 1 that grows with thickness; practical tables for caesium-137 in lead quote nearer 6.5 mm per halving. Charged particles do not attenuate exponentially at all: they stop at a range.

6What a dose figure does not say

A dose is the mass average of a random process, and at low dose the randomness shows. One milligray of gamma rays sends, on average, about one electron track through each cell nucleus. Track numbers are Poisson distributed, so a fraction e(−1) = 37% of nuclei receive none while others receive two or three: one milligray describes the average, not any cell. Risk inherits that structure. For protection at low dose, ICRP assumes a linear, no-threshold nominal risk of about 5 × 10⁻² per sievert, averaged over ages and both sexes and close to the chance of a fatal cancer, so an effective dose of 10 mSv adds about 5 × 10⁻⁴ to that chance, beside a lifetime baseline near 20% of dying of cancer. That is an expectation across many people, and E itself is computed for a reference phantom, not for anyone's organs. At high doses, above roughly 0.5 to 1 Gy, tissue reactions with thresholds take over, and doses are then quoted in grays to the organ, not in sieverts.

2

Key equations

Read the units, assumptions and limits before substituting.

Absorbed dose

D = dε̄/dm

A per-mass average: the same number whether a fingertip or the whole body is irradiated, and blind to which particle carried the energy.

ε̄ mean energy imparted (J), m mass (kg); D in Gy = J kg⁻¹, and always a dose to a named material

Equivalent dose to a tissue

HT = wR DT

Rescales for ionisation density: 1 mGy of alpha particles counts as 20 mSv. Sv and Gy are both J kg⁻¹, so the unit name carries the distinction.

DT mean dose to tissue T (Gy); wR dimensionless: 1 photons, electrons; 2 protons; 20 alphas; HT in Sv; mixed fields sum over R

Effective dose

E = ΣT wT HT, with ΣT wT = 1

The normalisation makes a uniform dose give E = H, so a partial-body exposure lands on the whole-body scale and can be compared with background.

wT dimensionless: 0.12 lung, colon, stomach, red marrow, breast; 0.04 thyroid; 0.01 skin; E in Sv

Dose rate from a point gamma source

Ḋ = y A Eγ (μₑₙ/ρ) / (4π r²)

Energy conservation over a sphere gives the 1/r². For caesium-137 it predicts 84 µGy h⁻¹ at 1 m per GBq.

A activity (Bq), y photons per decay, Eγ photon energy (J), μₑₙ/ρ tissue absorption (m² kg⁻¹), r (m); Ḋ in Gy s⁻¹

Narrow-beam attenuation

I(x) = I₀ e(−μx)

Solves dI/dx = −μI: a fixed interaction chance per unit length. e(−μx) is the probability that one photon crosses uncollided.

μ linear attenuation coefficient (m⁻¹), x shield thickness (m); μ = (μ/ρ)ρ from tabulated μ/ρ in m² kg⁻¹

Half-value thickness

x₁/₂ = ln 2 / μ

n half-value thicknesses transmit 2⁻ⁿ; ten of them cut the beam about a thousandfold, since 2¹⁰ = 1024.

x₁/₂ in m, μ in m⁻¹; lead at 662 keV: μ ≈ 126 m⁻¹, so x₁/₂ ≈ 5.5 mm
3

Interactive lab

Predict first. Explore the model. Compare the result.

Explore the model

1.0 GBq
0.2 to 2 GBq; steps of 0.1.
5.5 mm
0 to 22 mm; steps of 0.5.
1.00 m
0.25 to 8 m; steps of 0.25.

Try this. With no lead, move r from 1 m to 2 m: the rate falls fourfold, 84 to 21 µSv h⁻¹. Back at 1 m, add 11 mm of lead instead: two half-value layers buy the same factor of four. Then thicken the lead until the solid line meets background inside the frame.

Live results

HALF-VALUE LAYERS d/x₁/₂
1.0
TRANSMISSION e(−μd)
0.500
DOSE RATE AT r
42.01 µSv h⁻¹
BACKGROUND REACHED AT
12.4 m

Results follow this lesson’s model and assumptions. Displayed values are rounded.

Interactive Physics III modelLog-log plot of the gamma dose rate from a 1.0 GBq caesium-137 point source against distance r. The dashed line is the bare source, falling as 1/r²; the solid line lies 5.5 mm of lead lower, a narrow-beam factor e^(−μd) = 0.500. At r = 1.00 m the marker reads 42.01 µSv h⁻¹; the faint line is natural background, 0.27 µSv h⁻¹.dose rate, µSv h⁻¹10³100.10.25 m1 m4 mdashed: no shieldsolid: 5.5 mm lead = 1.0 x₁/₂background 0.27 µSv h⁻¹at r = 1.00 m: 42.01 µSv h⁻¹, 153.3 × background
Log-log plot of the gamma dose rate from a 1.0 GBq caesium-137 point source against distance r. The dashed line is the bare source, falling as 1/r²; the solid line lies 5.5 mm of lead lower, a narrow-beam factor e(−μd) = 0.500. At r = 1.00 m the marker reads 42.01 µSv h⁻¹; the faint line is natural background, 0.27 µSv h⁻¹.

Predict → change one variable → check

Plan a change before running it. Every other input stays at the saved baseline.

Saved baseline. Source activity A: 1.0 GBq; Lead thickness d: 5.5 mm; Distance r: 1.00 m

Baseline 1.0; choose 0.2 to 2, in steps of 0.1.
4. Compared with the saved baseline, this result will…

This experiment is kept only while this page is open. It does not change saved course progress.

4

Catch the common trap

The tempting reading is that a sievert figure measures the harm done to the person who received it, so that 10 mSv multiplied by 5% per sievert is that person's chance of a fatal cancer. It is not, for three reasons. The gray underneath is a mass average of energy that, at low dose, arrives as discrete tracks, so many cells receive nothing at all. The sievert multiplies that average by rounded weighting factors defined for a reference person and measured on nobody. And the 5 × 10⁻² Sv⁻¹ coefficient is a linear, no-threshold extrapolation adopted for protection and averaged over a population of ages and sexes. A dose figure supports comparisons, with background, with a limit, with another procedure, and an expected number of cases among many people. For one individual it sets only a nominal probability; the outcome itself is a draw.

5

Practice & worked examples

3 authored examples. Make an attempt, then reveal the reasoning one step at a time.

EasyExample 1

Over one month, the 1.2 kg of an adult's lungs absorbs 3.6 × 10⁻⁵ J from alpha particles emitted by inhaled radon progeny. Find the absorbed dose, the equivalent dose to the lungs and the effective dose (lung wT = 0.12), and compare the last with one month of natural background at 2.4 mSv a year.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

MediumExample 2

A 0.40 GBq caesium-137 calibration source emits 0.851 photons of 662 keV per decay. Taking μₑₙ/ρ = 3.26 × 10⁻³ m² kg⁻¹ for tissue and ignoring absorption in air, find the dose rate 0.50 m from it, then the distance at which the rate falls to 7.5 µSv h⁻¹.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

HardExample 3

A technician will work 0.60 m from a vial of technetium-99m for the first 2.0 h after it is calibrated at 8.0 GBq (t½ = 6.0 h; 0.89 photons of 140 keV per decay). Take μₑₙ/ρ = 2.7 × 10⁻³ m² kg⁻¹ for tissue and a narrow-beam μ = 27 cm⁻¹ for lead at 140 keV. What thickness of lead keeps her dose over the two hours to 10 µSv?

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

6

Quick check

Select an answer and explain it before checking.

Worker P gets 1.0 mGy of gamma rays to the whole body; Q gets 1.0 mGy of alpha particles to the lungs (wT = 0.12). Whose effective dose is larger?
7

Review & continue

Absorbed dose is the energy ionising radiation deposits per kilogram of matter, measured in grays (1 Gy = 1 J kg⁻¹); equivalent and effective dose, in sieverts, weight it for radiation type and for the tissues exposed.

  • Explain the relationship without looking at the equation.
  • Check a sign, a unit and a model assumption in your working.
  • Return to the lab or worked example if a step is still unclear.

Optional supporting lessons

These chapter resources can help with earlier ideas; they are not additional required Physics III completion tasks.

Extra challenging questions

Connect several ideas, explore supplied data, and compare your reasoning with a worked solution.