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Optional unit · institution-dependent · Interactive lesson

Resonance fluorescence: Mollow triplet and antibunching

This is where the optical Bloch equations meet a photodetector. One atom and one resonant laser give two measurements: a spectrometer finds three lines where a classical scatterer gives one, and a pair of counters never clicks together. Both follow from the atom's lowering operator, and the second is light no classical wave can imitate.

UAQM-14.07 · Lesson 7 of 9 in this unit. Position is not a completion score.
Starting model: Resonance fluorescence: Mollow triplet and antibunchingTop: the inelastic spectrum of one atom driven on resonance at Ω = 3.0Γ, per scattered photon, against (ω − ω_L)/Γ from −8 to +8, computed exactly from the Bloch equations with the regression theorem; dashed lines mark ±Ω′ = ±2.99Γ, and the arrow is the elastic delta function at ω_L, 5.3% of the light. Bottom: g⁽²⁾(τ) for Γτ from 0 to 8.inelastic S(ω)arrow: elastic 5%(ω − ωL)/Γ from −8 to +8g⁽²⁾(τ), one atom10Γτ = 8
Start with a picture. Change the model in the lab below.

Optional unit · institution-dependent. Units 14 and 15 are the course’s optional extension into open systems and quantum gases. Unit 14 builds on radiation and decay; Unit 15 builds on second quantisation. Keep the fifteen-unit numbering and follow your institution’s required syllabus. Optional work is not a required completion gate.

1

Build the model

One driven atom scatters light into three lines, and never two photons at once.

The key idea

Resonance fluorescence is the light a single two-level atom scatters while a laser near its transition drives it, and every measurable property of that light is a correlation function of the atom's lowering operator σ₋.

Example. A sodium atom driven on resonance at Ω = 2π × 50 MHz, about 5.1Γ, scatters 3.0 × 10⁷ photons s⁻¹: 1.9% elastically at ωL, the rest into lines at ωL and ωL ± 2π × 49.9 MHz, and never two photons at the same instant.

The complete physical model and assumptions

Drive one two-level atom with a resonant laser and ask what light comes out. The answer is already in the atom: in the far zone the positive-frequency scattered field is a classical dipole field with d e(−iω₀t) replaced by d σ₋ at the retarded time, a result outlined from Unit 11's mode equations, so every normally ordered photodetection signal is an atomic correlation function. The mean ⟨σ₋⟩ radiates coherently, an elastic delta function at the laser frequency ωL carrying a fraction 1/(1 + s) of the light, with s = 2Ω²/Γ². The fluctuations radiate the rest, and once the quantum regression theorem is quoted their two-time correlation obeys the optical Bloch equations: the decay constants −Γ/2 and −3Γ/4 ± iΩ′ become a line at ωL of full width Γ and two at ωL ± Ω′ of full width 3Γ/2, which for Ω ≫ Γ carry weights 1:2:1 and stand in heights 1:3:1, the Mollow triplet. Read by two detectors, the same field gives g⁽²⁾(τ), and a detection leaves the atom in |g⟩, so g⁽²⁾(τ) is the excited population regrowing from zero and g⁽²⁾(0) = 0, which no classical intensity allows. The model stops where its approximations do: the Born-Markov treatment of the vacuum needs Γ and Ω far below ω₀, the laser must be narrower than Γ, atomic motion and other atoms blur both the lines and the dip, and in a cavity whose coupling beats its losses the photon comes back and the master equation fails.

1The detector reads the atom's lowering operator

Units are SI with ħ explicit; nothing here is relativistic, so the course's metric signature (+, −, −, −) never enters. Unit 11's mode equations, integrated with the atom as a source, split each mode operator into a free part and a part driven by σ₋ at earlier times. Summing the driven parts over modes, with the Markov step that treats σ₋e(iω₀t) as slow, gives in the far zone the classical dipole field with d e(−iω₀t) replaced by d σ₋(t − r/c): outlined here, not derived in full. The free part annihilates the vacuum, so a detector, which measures normally ordered products, sees only the atom: the intensity is 2ε₀c|ψ|²ρₑₑ, with |ψ| = ω₀²d sin θ/(4πε₀c²r) in V m⁻¹. Over a sphere the sin²θ pattern integrates to 8π/3 and the power to ω₀⁴d²ρₑₑ/(3πε₀c³) = ħω₀Γρₑₑ, so the photon flux is Γρₑₑ with Unit 12's Γ, a check on the normalisation. For sodium's D2 line the measured 16.25 ns lifetime gives Γ = 6.15 × 10⁷ s⁻¹, so one atom scatters at most Γ/2 = 3.1 × 10⁷ photons s⁻¹.

2Mean and fluctuation: elastic and inelastic light

Write σ₋ = ⟨σ₋⟩ + δσ₋. The correlation splits into |⟨σ₋⟩|², which never decays and so transforms into a delta function at ωL, and ⟨δσ₊(t + τ)δσ₋(t)⟩, which decays and gives lines of finite width. The first is elastic scattering by the atom's mean dipole, as sharp as the laser; the second is fluorescence proper. Topic 14.06's resonant steady state, used here, has ρₑₑ = Ω²/(Γ² + 2Ω²) and |⟨σ₋⟩|² = Ω²Γ²/(Γ² + 2Ω²)², so the elastic fraction is 1/(1 + s), derived, with s = 2Ω²/Γ² = I/Iₛₐₜ and Iₛₐₜ = πhcΓ/(3λ³) = 6.26 mW cm⁻² for sodium, computed from the measured Γ and λ. The limits check it. As Ω → 0 all the light is elastic: the atom responds linearly, like a driven classical dipole, and this is Rayleigh scattering. As s grows the atom scatters faster, ρₑₑ → ½, yet the Bloch vector shrinks to the centre of the ball and the mean dipole vanishes, so the elastic fraction falls as 1/s, to 1.9% at Ω = 5.1Γ. Inelastic light is the price of saturation, a nonlinearity no linear oscillator has.

3Regression: the Bloch equations run in τ

To evaluate ⟨δσ₊(t + τ)δσ₋(t)⟩ we quote the quantum regression theorem: under the Born-Markov approximations a two-time average ⟨A(t + τ)B(t)⟩ obeys, in τ, the same linear equations as ⟨A(t + τ)⟩, starting from ⟨A(t)B(t)⟩. For fluctuations these are the homogeneous Bloch equations. On resonance, in Bloch components, du/dt = −Γu/2, dv/dt = −Γv/2 − Ωw and dw/dt = −Γw + Ωv, so the decay constants are −Γ/2 and the roots of (λ + Γ/2)(λ + Γ) + Ω² = 0, which are λ = −3Γ/4 ± iΩ′ with Ω′ = √(Ω² − Γ²/16), derived. Each constant becomes a line centred by its imaginary part, with half-width minus its real part: a Lorentzian at ωL of full width Γ and a pair at ωL ± Ω′ of full width 3Γ/2, which also carry a dispersive part, of relative size about 5Γ/(4Ω′) for Ω ≫ Γ, that pulls their maxima slightly inside ±Ω′. The initial values ⟨σᵢσ₋⟩ − ⟨σᵢ⟩⟨σ₋⟩ fix the weights, and the inelastic area is ρₑₑ − |⟨σ₋⟩|², as it must be. Carried through exactly, this gives the closed form the figure draws at every Ω, and a direct numerical integration of the master equation reproduces it to five decimal places.

4Dressed states count the weights 1:2:1

Why three lines, and why 1:2:1, is clearest for Ω ≫ Γ with dressed states. In the frame rotating at ωL the resonant Hamiltonian (ħΩ/2)(σ₊ + σ₋) has eigenstates |±⟩ = (|g⟩ ± |e⟩)/√2 split by ħΩ; counting laser photons, each manifold of N photons is such a doublet, the next ħωL lower. Emission takes the atom from manifold N to N − 1 through σ₋, whose four elements ⟨±|σ₋|±⟩ and ⟨∓|σ₋|±⟩ all have modulus ½, so each transition runs at Γ/4 per unit population: |+⟩ → |+⟩ and |−⟩ → |−⟩ at ωL, |+⟩ → |−⟩ at ωL + Ω, |−⟩ → |+⟩ at ωL − Ω. The cross rates balance, so the populations are ½ each and the lines carry Γ/8, Γ/4 and Γ/8: weights 1:2:1 summing to Γρₑₑ = Γ/2, derived. Divided by the widths 3Γ/2, Γ and 3Γ/2 they give heights 1:3:1. For sodium at Ω = 2π × 100 MHz the lines lie 100 MHz apart, with full widths 9.8 MHz and 14.7 MHz. Measured, quoted: Schuda, Stroud and Hercher saw the triplet in a sodium beam in 1974, and Wu, Grove and Ezekiel in 1975, crossing laser and beam at right angles to remove the Doppler width, found its spacing and heights in good agreement with Mollow's theory.

5A detection resets the atom: g⁽²⁾(τ) derived

Two detectors measure Glauber's coincidence rate G⁽²⁾(τ) ∝ ⟨E⁽⁻⁾(t)E⁽⁻⁾(t + τ)E⁽⁺⁾(t + τ)E⁽⁺⁾(t)⟩, which the source field turns into ⟨σ₊(t)σ₊(t + τ)σ₋(t + τ)σ₋(t)⟩. Read it as a measurement. The first detection applies σ₋, and σ₋ρₛₛσ₊ = ρₑₑ|g⟩⟨g| whatever ρₛₛ was: a photon has just left, so the atom is certainly in its ground state. In the Markov approximation that photon never returns, so the master equation evolves |g⟩⟨g| for a time τ and the second detection comes at rate Γρₑₑ(τ), with ρₑₑ(0) = 0. So G⁽²⁾ ∝ Γρₑₑ × Γρₑₑ(τ), and dividing by (Γρₑₑ)², the rate of uncorrelated pairs, gives g⁽²⁾(τ) = ρₑₑ(τ)/ρₑₑ(∞), derived; the regression theorem returns the same expression. On resonance the Bloch equations solved from w = −1 give the closed form 1 − e(−3Γτ/4)[cos Ω′τ + 3Γ/(4Ω′) sin Ω′τ]. Checks: g⁽²⁾(0) = 0 at every Ω; g⁽²⁾ → 1 as τ → ∞, independent detections; for Ω ≪ Γ the roots turn real and g⁽²⁾ = (1 − e(−Γτ/2))²; for Ω ≫ Γ it rings, first peaking at Ω′τ = π at 1 + e(−3πΓ/(4Ω′)), which is 1.45 at Ω = 3Γ.

6No classical intensity can do this

A classical field gives the detectors a non-negative intensity I(t). Then g⁽²⁾(0) = ⟨I²⟩/⟨I⟩² = 1 + Var(I)/⟨I⟩² ≥ 1, shown, and for stationary light Cauchy-Schwarz, ⟨I(t)I(t + τ)⟩ ≤ √(⟨I(t)²⟩⟨I(t + τ)²⟩) = ⟨I²⟩, gives g⁽²⁾(τ) ≤ g⁽²⁾(0). Thermal light sits at 2 and an ideal laser at 1. One atom breaks both bounds: g⁽²⁾(0) = 0 is sub-Poissonian, and g⁽²⁾ rising from it is antibunching, photons spaced by the time to re-excite, about half a Rabi period under strong drive and a few lifetimes under weak. Measured, quoted: in 1977 Kimble, Dagenais and Mandel crossed a sodium beam with a resonant laser and saw coincidences rise from a minimum at τ = 0 over roughly the 16 ns lifetime, the first light shown to need a quantum description. Their beam held a fluctuating number of atoms, whose independent photons pull g⁽²⁾(0) up towards 1, so sub-Poissonian counts waited for Short and Mandel in 1983, and a single stored ion in 1987 removed the averaging over atoms altogether.

2

Key equations

Read the units, assumptions and limits before substituting.

Source field of the atom (outlined)

E⁽⁺⁾(r, t) = E⁽⁺⁾free(r, t) + [ω₀²/(4πε₀c²r)] d⊥ σ₋(t − r/c)

Outlined from Unit 11, not derived in full. Detector signals become atomic correlations; integrating 2ε₀c⟨E⁽⁻⁾⋅E⁽⁺⁾⟩ over a sphere returns ħω₀Γρₑₑ, Unit 12's photon rate.

far zone, r ≫ λ; d = ⟨g|d|e⟩ in C m; d⊥ = (r̂ × d) × r̂, of size d sin θ; ω₀ in rad s⁻¹; ε₀ in F m⁻¹; E in V m⁻¹

Spectrum from a two-time correlation

S(ω) = (1/π) Re ∫₀(∞) dτ e(−iωτ) ⟨σ₊(t + τ) σ₋(t)⟩ₛₛ

The Wiener-Khinchin theorem applied to the source field, quoted. Evaluating the correlation needs the regression theorem, also quoted: in τ it obeys the Bloch equations.

S in s, per unit ω in rad s⁻¹, with ∫S dω = ρₑₑ; σ₋ = |g⟩⟨e| is dimensionless; ss marks the driven steady state

Elastic fraction on resonance

Pcoh/P = |⟨σ₋⟩ₛₛ|²/ρₑₑ = Γ²/(Γ² + 2Ω²) = 1/(1 + s)

Derived from the Bloch steady state of topic 14.06. Ω → 0 is pure Rayleigh scattering; at s ≫ 1 the atom scatters fastest while its mean dipole ⟨σ₋⟩ tends to zero.

Γ = A coefficient and Ω = d⋅E₀/ħ, both in s⁻¹; s = 2Ω²/Γ² = I/Iₛₐₜ; the elastic part is a delta function at ωL

Mollow triplet, Ω ≫ Γ, on resonance

Sinc(ω) ≈ ρₑₑ[¼L(ωL − Ω′, 3Γ/2) + ½L(ωL, Γ) + ¼L(ωL + Ω′, 3Γ/2)]

Derived, given the regression theorem: the Bloch decay constants −Γ/2 and −3Γ/4 ± iΩ′ set centres and widths. Weights 1:2:1 over widths 3:2:3 give peak heights 1:3:1.

L(ωc, w) is a unit-area Lorentzian of full width w centred on ωc, in s; Ω′ = √(Ω² − Γ²/16) in rad s⁻¹

Photon correlation of one atom, on resonance

g⁽²⁾(τ) = 1 − e(−3Γτ/4)[cos Ω′τ + 3Γ/(4Ω′) sin Ω′τ]

Derived: a detection leaves σ₋ρσ₊ ∝ |g⟩⟨g|. g⁽²⁾(0) = 0 at every Ω, and the first maximum, at Ω′τ = π, is 1 + e(−3πΓ/(4Ω′)).

the excited population regrowing from |g⟩ over its steady value; dimensionless; below Ω = Γ/4, cos and sin become cosh and sinh

Classical bound on intensity correlations

g⁽²⁾(0) = ⟨I²⟩/⟨I⟩² = 1 + Var(I)/⟨I⟩² ≥ 1

Shown in one line. One atom breaks it at τ = 0, and as g⁽²⁾ rises it also breaks the Cauchy-Schwarz bound g⁽²⁾(τ) ≤ g⁽²⁾(0): sub-Poissonian and antibunched.

I(t) ≥ 0 is any classical, stationary intensity in W m⁻²; Var(I) = ⟨I²⟩ − ⟨I⟩²
3

Interactive lab

Predict first. Explore the model. Compare the result.

Explore the model

3.0 Γ
0.5 to 6 Γ; steps of 0.1.
1.0
0 to 8; steps of 0.2.

Try this. Start at Ω = 0.5Γ: two thirds of the light is in the arrow and the inelastic part is one hump, yet g⁽²⁾(0) is already 0. Drag Ω up: the arrow shrinks, the sidebands walk out to just inside the dashed ±Ω′ and settle near a third of the central height, and g⁽²⁾ rings at Ω′.

Live results

ELASTIC FRACTION
5.3 %
SIDEBAND OFFSET Ω′
2.99 Γ
g⁽²⁾ AT THE DOT
1.449
FIRST g⁽²⁾ MAXIMUM
1.455

Results follow this lesson’s model and assumptions. Displayed values are rounded.

Interactive Advanced Quantum Mechanics modelTop: the inelastic spectrum of one atom driven on resonance at Ω = 3.0Γ, per scattered photon, against (ω − ω_L)/Γ from −8 to +8, computed exactly from the Bloch equations with the regression theorem; dashed lines mark ±Ω′ = ±2.99Γ, and the arrow is the elastic delta function at ω_L, 5.3% of the light. Bottom: g⁽²⁾(τ) for Γτ from 0 to 8.inelastic S(ω)arrow: elastic 5%(ω − ωL)/Γ from −8 to +8g⁽²⁾(τ), one atom10Γτ = 8
Top: the inelastic spectrum of one atom driven on resonance at Ω = 3.0Γ, per scattered photon, against (ω − ωL)/Γ from −8 to +8, computed exactly from the Bloch equations with the regression theorem; dashed lines mark ±Ω′ = ±2.99Γ, and the arrow is the elastic delta function at ωL, 5.3% of the light. Bottom: g⁽²⁾(τ) for Γτ from 0 to 8.

Predict → change one variable → check

Plan a change before running it. Every other input stays at the saved baseline.

Saved baseline. Rabi frequency Ω: 3.0 Γ; Delay Γτ at the dot: 1.0

Baseline 3.0; choose 0.5 to 6, in steps of 0.1.
4. Compared with the saved baseline, this result will…

This experiment is kept only while this page is open. It does not change saved course progress.

4

Catch the common trap

Drive the atom weakly and almost all of its light is elastic: at Ω = 0.2Γ, 93% sits in the delta function at ωL, as narrow as the laser. The tempting conclusion is that this light is laser-like, photons arriving at random with g⁽²⁾(0) = 1, and that antibunching, like the triplet, needs strong driving. It does not. g⁽²⁾(0) = 0 at every Ω, because a detection leaves the atom in |g⟩ whatever state it was in, and at Ω ≪ Γ the dip is g⁽²⁾(τ) = (1 − e(−Γτ/2))², still only 0.15 at τ = 1/Γ. The spectrum is a first-order property, set by ⟨σ₊(t + τ)σ₋(t)⟩; photon statistics are second-order, set by ⟨σ₊σ₊σ₋σ₋⟩, and one does not fix the other. The zero is an interference: σ₋² = 0 forces the fluctuations' pair amplitude ⟨δσ₋δσ₋⟩ to equal −⟨σ₋⟩², cancelling exactly the pairs the elastic part alone would carry.

5

Practice & worked examples

3 authored examples. Make an attempt, then reveal the reasoning one step at a time.

EasyExample 1

A sodium atom on its D2 cycling transition, Γ/2π = 9.79 MHz, is driven on resonance with Ω/2π = 50.0 MHz. Find the elastic fraction of the scattered light, the photon rate, and the positions, full widths, shares of the inelastic power and peak-height ratio of the three Mollow lines.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

MediumExample 2

A sodium atom (λ = 589.2 nm, Γ = 6.15 × 10⁷ s⁻¹) at the origin has its transition dipole along z and is driven on resonance at Ω = Γ. A photodiode of area 1.0 mm² faces it from r = 2.0 cm in the equatorial plane. Find d from Γ, then from the source field the field scale |ψ|, the intensity and the photon flux at the diode, and check the flux against Γρₑₑ.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

HardExample 3

Sodium atoms (Γ = 6.15 × 10⁷ s⁻¹) are driven on resonance at Ω = 3.0Γ. For one atom, find the delay and height of the first maximum of g⁽²⁾(τ). A beam then holds a Poisson-distributed number of atoms, mean ⟨N⟩ = 1.5, in view for about 1 μs. Treating the atoms as independent, with position-dependent cross terms averaging to zero, find g⁽²⁾ at τ = 0, at that maximum and on the plateau 1/Γ ≪ τ ≪ 1 μs, and compare a fixed N = 2.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 6 steps revealed.

6

Quick check

Select an answer and explain it before checking.

A two-level atom is driven exactly on resonance with Rabi frequency Ω = 20Γ, and its fluorescence passes through a spectrometer whose resolution is much finer than Γ. Which description of the inelastic spectrum is correct?
7

Review & continue

Resonance fluorescence is the light a single two-level atom scatters while a laser near its transition drives it, and every measurable property of that light is a correlation function of the atom's lowering operator σ₋.

  • Explain the relationship without looking at the equation.
  • Check a sign, a unit and a model assumption in your working.
  • Return to the lab or worked example if a step is still unclear.

Extra challenging questions

Connect several ideas, explore supplied data, and compare your reasoning with a worked solution.