
Optional unit · institution-dependent · Interactive lesson
Dispersion, aberrations, and ray-model limits
Every lens you have drawn so far had one focal length and rays that behaved. Neither survives contact with real glass. This is the lesson where colour splits a focus, a spherical surface bends its own edges too hard, designers cancel both, and the ray model finally admits what it cannot do.
UPII-13.08 · Lesson 8 of 8 in this unit. Position is not a completion score.Optional unit · institution-dependent. Your university may teach this optics or introductory modern-physics material separately. Follow your institution’s required sequence. Optional work is not a required completion gate.
Build the model
A single refractive index is a convenient fiction, and it has a price.
The key idea
Dispersion is the dependence of a material's refractive index on wavelength, so each colour in a beam refracts through its own angle at one and the same surface.
Example. A 6.0° F2 flint prism deviates the 486 nm blue line by 3.79° and the 656 nm red line by 3.69°: one wedge of glass has turned a single symbol n into a 0.10° fan of colour.
The complete physical model and assumptions
A ray diagram carries two silent assumptions: that the glass has one refractive index, and that every ray stays close enough to the axis for sin θ ≈ θ. Both are measurably false. Bound electrons in glass resonate in the ultraviolet, so the closer a wavelength lies to that resonance the more strongly the medium responds, and n rises as λ falls — by about 0.008 across the visible for a crown glass. That one fact splits white light in a prism and gives a lens a different focal length for every colour, chromatic aberration, whose size is set by the focal length and the glass's Abbe number and by nothing else — no aperture enters it. Drop the paraxial assumption and a second failure appears in strictly one colour: a spherical surface brings marginal rays to a focus nearer than paraxial ones, spherical aberration, growing as the square of the ray height. Both defects are geometric, so both can be engineered away — colour by pairing two glasses whose dispersions cancel, shape by aspheric surfaces, lens bending or a smaller stop. What cannot be engineered away is the wave nature of light. Once the aberrations fall below about λf/D, the image of a point is an Airy disc, and geometric optics has nothing further to say.
1One glass does not have one index
A ray diagram writes n as a constant of the material. Measure it and it is a function of wavelength. The reason is resonance: the bound electrons of a transparent glass have their absorption bands in the ultraviolet, and the closer a wavelength sits to a band, the harder the electrons are driven and the more the wave is retarded. Blue light, nearer the band, sees a larger n than red. Across the visible this is normal dispersion, dn/dλ < 0, and for BK7 crown the measured indices are 1.52238 at 486.1 nm, 1.51680 at 587.6 nm and 1.51432 at 656.3 nm — a spread of only 0.00806, and quite enough to matter. Cauchy's fit n = A + B/λ² captures it: forced through the F and C values it gives A = 1.5045 and B = 0.00422 μm², and then predicts n at 587.6 nm as 1.51674 against 1.51680 measured. Inside an absorption band the trend reverses, anomalous dispersion, and the two-term fit fails; that is why glass catalogues use the longer Sellmeier form.
2Turning the index spread into an angle
Snell's law already holds the whole effect: sin θ₁ = n sin θ₂ with a different n for each colour returns a different θ₂ for each colour, so a single refracting surface fans white light out. A prism is the useful version because its two faces push the same way instead of cancelling. For a thin prism of apex angle A the deviation is δ = (n − 1)A, so the angular spread between the F and C lines is Δδ = (nF − nC)A, which is the same thing as δd/Vd. A 6.0° F2 flint wedge, with nF = 1.63208 and nC = 1.61503, deviates 486 nm by 3.79° and 656 nm by 3.69°: a 0.10° fan, six arcminutes, out of a piece of glass you could balance on a fingertip. A thick prism is handled at minimum deviation, where the ray crosses symmetrically and n = sin((A + δₘᵢₙ)/2)/sin(A/2) — the standard bench method for measuring an index to four decimal places, one colour at a time.
3The same spread blurs an image
A thin lens has power P = (n − 1)(1/R₁ − 1/R₂), and of those factors only n depends on colour, so P is proportional to (n − 1) and the fractional spread in power is exactly (nF − nC)/(nd − 1) = 1/Vd. That line is the whole of first-order chromatic aberration: the blue focus sits nearer the lens than the red one, by fC − fF ≈ fd/Vd. A 100 mm BK7 singlet therefore splits its foci by 1.56 mm, an enormous distance when depth of focus is measured in tens of micrometres. That separation along the axis is longitudinal chromatic aberration. Put a screen halfway between the two foci and each cone has reopened to a diameter of about a/Vd, where a is the aperture radius: 0.195 mm for a = 12.5 mm, and that width is the transverse blur the split produces. Off axis a second form appears, because magnification depends on focal length too, so the colours land at different heights — the fringing you see at the corners of a cheap photograph but never at its centre.
4Spherical aberration survives in one colour
Now set colour aside and use a single wavelength: a spherical surface still fails. The paraxial results were built on sin θ ≈ θ, and a wide beam breaks that approximation. For a concave mirror of radius R, a ray arriving parallel to the axis at height h crosses the axis exactly R − R/(2 cos θ) from the vertex, where sin θ = h/R. Take R = 240 mm. The paraxial focus is at 120.0 mm, while the ray at h = 48 mm crosses at 117.53 mm, 2.47 mm short; at h = 24 mm the shortfall is 0.605 mm, almost exactly a quarter, because expanding the exact expression leaves an error growing as h². The failing rays do not scatter at random either — their envelope is a caustic, the bright cusp you see on the surface of a coffee cup. Lenses misbehave the same way, and for a simple converging element the marginal rays always focus nearer than the paraxial ones, so the tightest spot sits just inside the paraxial focus.
5Two ways to cancel a geometric defect
Colour and shape need different cures. For colour, combine two glasses: thin lenses in contact add powers, P₁ + P₂ = P, and the pair is achromatic when P₁/V₁ + P₂/V₂ = 0. Because V is always positive, the two powers must carry opposite signs — a strong crown cemented to a weaker flint. For f = 200.0 mm from BK7 (V = 64.1) and F2 (V = 36.4) that gives P₁ = +11.57 D and P₂ = −6.57 D. The pair brings 486 nm and 656 nm to one focus, but the wavelengths between still miss it by a residual secondary spectrum of roughly f/2200, and removing that needs a third glass, an apochromat. Spherical aberration answers to geometry instead: bend the lens so the deviation is shared between its two surfaces, replace a surface with an asphere or a paraboloid, or simply close a stop, which bites hard on an h² law. And a mirror has no dispersion at all, which is one reason every large telescope objective is a mirror.
6Where the ray model gives out
Every defect so far is geometric, so in principle every one can be designed away. Light does not allow it. An aperture of diameter D diffracts, and the image of a point through a perfect circular lens is an Airy disc whose first dark ring subtends θₘᵢₙ = 1.22 λ/D, a diameter of 2.44 λf/D in the focal plane. For f = 100 mm, D = 25 mm and λ = 550 nm that is 5.4 μm. Set it beside the 195 μm chromatic blur of the BK7 singlet of the same size: the singlet is aberration-limited by a factor of 36, so correcting it is worth the money. Once corrected, further polishing buys nothing and the lens is called diffraction-limited. The ray model is the λ → 0 limit of wave optics, trustworthy while every aperture and structure is large compared with λ; near a focus, at an edge, or in a slit a few wavelengths wide it stops being an approximation and starts being wrong.
Key equations
Read the units, assumptions and limits before substituting.
Cauchy's two-term dispersion
n(λ) = A + B/λ²
Two measured indices fix A and B: BK7 gives A = 1.5045 and B = 0.00422 μm², then predicts n = 1.51674 at 587.6 nm against 1.51680 measured.
λ is the vacuum wavelength in μm, so B is in μm²; A and n are dimensionlessAbbe number of a glass
Vd = (nd − 1)/(nF − nC)
One number ranks a glass for colour: crowns sit near 64, flints near 36, and a large Vd means a small spread.
indices at 587.6 nm (d), 486.1 nm (F) and 656.3 nm (C); Vd is dimensionlessDeviation by a thin prism
δ = (n − 1)A
Each colour gets its own δ, so the fan a wedge opens is Δδ = δd/Vd, only 0.10° for a 6.0° F2 prism.
apex angle A and deviation δ in the same angular unit; valid for A below about 10°Chromatic focal split of a thin lens
fC − fF ≈ fd/Vd
The entire colour error of a singlet from one catalogue number: a 100 mm BK7 lens splits its foci by 1.56 mm.
f in metres or millimetres, the same unit throughout; Vd dimensionlessAchromatic doublet condition
P₁/V₁ + P₂/V₂ = 0
Forces opposite signs on the two powers: a strong crown with a weaker flint, cancelling colour while keeping net power.
powers P = 1/f in dioptres (m⁻¹); elements in contact also satisfy P₁ + P₂ = PRayleigh limit of a circular aperture
θₘᵢₙ = 1.22 λ/D
Where the ray model ends: a point images as an Airy disc of diameter 2.44 λf/D, just 5.4 μm for f = 100 mm and D = 25 mm at 550 nm.
θₘᵢₙ in radians; λ and the aperture diameter D in the same length unitInteractive lab
Predict first. Explore the model. Compare the result.
Explore the model
Try this. Drag the Abbe number from 20 to 70 and watch the two focal marks close together, then open the aperture: the marks do not move at all, while the blur trapped between them grows.
Live results
- f AT 486 nm, F LINE
- 99.17 mm
- f AT 656 nm, C LINE
- 100.83 mm
- COLOUR SPLIT
- 1.667 mm
- AIRY SPOT AT 550 nm
- 0.0056 mm
Results follow this lesson’s model and assumptions. Displayed values are rounded.
Predict → change one variable → check
Plan a change before running it. Every other input stays at the saved baseline.
Saved baseline. Focal length fd: 100 mm; Abbe number Vd: 60; Aperture radius a: 12 mm
This experiment is kept only while this page is open. It does not change saved course progress.
Catch the common trap
The commonest move is to treat stopping the lens down as a cure for colour. It is not. The longitudinal split between the blue and red foci is fC − fF ≈ fd/Vd, which contains the focal length and the glass and no aperture at all, so closing the iris to a pinhole still leaves the two colours focusing on different planes. What the stop does change is the blur that split produces, and only in proportion to the aperture radius, because the blur diameter is about a/Vd. Compare that with spherical aberration, whose longitudinal error falls as h² and whose blur falls as h³: stopping down really does kill it. So a photograph taken at f/16 looks sharper largely because spherical aberration and coma have collapsed, while the coloured fringes near the corners are still there. Colour needs a second glass, or a mirror, which has no dispersion to begin with.
Practice & worked examples
3 authored examples. Make an attempt, then reveal the reasoning one step at a time.
EasyExample 1
White light meets the flat face of an F2 flint block at 40.0° to the normal. The glass has n = 1.63208 for the 486 nm blue F line and n = 1.61503 for the 656 nm red C line. Find the refraction angle of each colour inside the glass, and the angle between the two refracted rays.
Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.
0 of 5 steps revealed.
- Snell's law at the entry face, with n = 1 in air: sin 40.0° = n sin θ, so sin θ = sin 40.0°/n, and sin 40.0° = 0.642788.
- Blue F line: sin θF = 0.642788/1.63208 = 0.393846, so θF = 23.194°.
- Red C line: sin θC = 0.642788/1.61503 = 0.398004, so θC = 23.453°.
- The fan between them is θC − θF = 0.259°, or 15.6 arcminutes. Blue carries the larger index, so it is bent further from its original direction — the ordering that normal dispersion always gives.
- Limiting check: set the two indices equal and the fan closes to zero, exactly as it must in a non-dispersive medium such as vacuum.
Answer. θF = 23.19° and θC = 23.45°, so the two refracted rays are separated by 0.26°, about 15.6 arcminutes, with blue the more strongly bent.
MediumExample 2
A concave spherical mirror has radius of curvature R = 240 mm. A ray parallel to the axis strikes it at height h = 48 mm. The reflected ray crosses the axis a distance R/(2 cos θ) from the centre of curvature, where sin θ = h/R. Find the crossing point measured from the vertex, compare it with the paraxial focus, then repeat for h = 24 mm.
Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.
0 of 6 steps revealed.
- Paraxial focus first: as θ → 0 the expression gives R/(2 cos θ) → R/2 = 120.0 mm from the centre of curvature, which puts the crossing 240 − 120.0 = 120.0 mm from the vertex. That is the focal length a ray diagram assumes for every ray.
- For h = 48 mm: sin θ = 48/240 = 0.2000, so θ = 11.537° and cos θ = 0.979796.
- The distance from the centre of curvature is R/(2 cos θ) = 240/(2 × 0.979796) = 122.474 mm, so measured from the vertex the ray crosses at 240 − 122.474 = 117.526 mm.
- Longitudinal spherical aberration = 120.000 − 117.526 = 2.474 mm, and the sign matters: the marginal ray focuses nearer the mirror, never further.
- For h = 24 mm: sin θ = 0.1000, cos θ = 0.994987, R/(2 cos θ) = 120.605 mm, crossing at 119.395 mm, an error of 0.605 mm.
- Halving the ray height cut the aberration from 2.474 mm to 0.605 mm, a factor of 4.09 — the h² law, which is why a stop is the cheapest cure available.
Answer. The marginal ray crosses 117.53 mm from the vertex, 2.47 mm inside the paraxial focus at 120.0 mm; at h = 24 mm the error is 0.605 mm, close to one quarter as large.
HardExample 3
Design a cemented achromatic doublet of focal length 200.0 mm from BK7 crown (V₁ = 64.1) and F2 flint (V₂ = 36.4), treating the two thin lenses as being in contact. Find the power and focal length of each element, then compare the residual colour error with that of a BK7 singlet of the same focal length, given that a standard crown-flint achromat leaves a secondary spectrum of roughly f/2200.
Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.
0 of 6 steps revealed.
- Thin lenses in contact add powers: P₁ + P₂ = P = 1/0.2000 m = 5.000 D.
- The first-order colour error of the pair vanishes when P₁/V₁ + P₂/V₂ = 0. Two equations, two unknowns.
- Substitute P₂ = P − P₁ into the achromatic condition: P₁/V₁ + (P − P₁)/V₂ = 0, which rearranges to P₁ = P V₁/(V₁ − V₂) = 5.000 × 64.1/27.7 = 11.570 D, and then P₂ = 5.000 − 11.570 = −6.570 D.
- Focal lengths: f₁ = 1/11.570 D = +86.43 mm for the converging crown, f₂ = 1/(−6.570 D) = −152.2 mm for the diverging flint. Check both conditions: 11.570 − 6.570 = 5.000 D, and 11.570/64.1 − 6.570/36.4 = 0.
- A BK7 singlet of the same focal length would split its foci by fd/Vd = 200.0/64.1 = 3.12 mm.
- The doublet puts 486 nm and 656 nm on one focus, leaving a secondary spectrum of about 200.0/2200 = 0.091 mm. The colour error has dropped by a factor of 34, paid for with a second element whose surfaces are more strongly curved.
Answer. Crown P₁ = +11.57 D (f₁ = +86.4 mm) and flint P₂ = −6.57 D (f₂ = −152 mm); the residual secondary spectrum is about 0.091 mm against the singlet's 3.12 mm split, a 34-fold gain.
Quick check
Select an answer and explain it before checking.
Review & continue
Dispersion is the dependence of a material's refractive index on wavelength, so each colour in a beam refracts through its own angle at one and the same surface.
- Explain the relationship without looking at the equation.
- Check a sign, a unit and a model assumption in your working.
- Return to the lab or worked example if a step is still unclear.
Optional supporting lessons
These chapter resources can help with earlier ideas; they are not additional required Physics II completion tasks.