Skip to main content

Physics II course sequence · Interactive lesson

Charge, conservation and quantisation

Before any force law, get the bookkeeping right. Charge carries a sign, moves only in whole electrons, and is never made or destroyed — so every electrostatics problem begins by asking what crossed the boundary and what the ledger reads afterwards.

UPII-01.01 · Lesson 1 of 8 in this unit. Position is not a completion score.
Starting model: Charge, conservation and quantisationCharge ledger for two objects. A starts at 0.0 nC and B at 0.0 nC, then 1.5 × 10¹⁰ electrons — carrying 2.40 nC of negative charge — move from A to B. The left bar is q_A, the middle bar q_B, and the right bar their sum, which no setting of the electron slider can shift.closed system: qA + qB cannot changemoved: 1.5 × 10¹⁰ electrons = 2.40 nCelectrons flow A → BqA = 2.40 nCqB = −2.40 nCsum = 0.00 nC+8 nC0−8 nC
Start with a picture. Change the model in the lab below.
1

Build the model

Charge comes in whole electrons, and the ledger always balances.

The key idea

Electric charge is the signed, conserved property of matter that comes only in whole multiples of the elementary charge e = 1.602176634 × 10⁻¹⁹ C, so any object's net charge is q = N e for some integer N — positive, negative or zero.

Example. A rubbed acetate rod reading −4.80 nC carries N = 4.80 × 10⁻⁹ C ÷ (1.602 × 10⁻¹⁹ C) = 3.00 × 10¹⁰ surplus electrons, a count and never a fraction of one — and the cloth that took them must read exactly +4.80 nC.

The complete physical model and assumptions

Electric charge is a property of matter with three hard rules attached, and most of first-semester electrostatics rests on them. It carries an algebraic sign, so charges add as signed numbers and a body holding 10²³ protons and 10²³ electrons behaves as though it held none. It is quantised: every free charge ever measured is a whole multiple of the elementary charge e = 1.602176634 × 10⁻¹⁹ C, a number the 2019 SI fixes exactly and then uses to define the ampere, so a free charge of half an electron is not a small charge but one that has never been found. And it is conserved: draw a closed boundary and the algebraic sum inside changes only by what crosses it, which is why rubbing, ionising, decaying and annihilating all leave the total untouched. The rules are experimental, not assumed — oil-drop measurements returned charges separated by one common step, and bulk matter is neutral to better than 10⁻²¹ e per atom, so the proton and electron charges must cancel exactly. Begin every problem by naming the boundary, then count what crosses it in whole electrons.

1Two signs, and what the sign buys you

Charge is not just an amount; it is an amount with an algebraic sign, and that is the whole reason ordinary matter is quiet. Rub glass with silk and wax with fur and the two rubbed objects attract; rub two pieces of glass the same way and they repel — the eighteenth-century evidence that there are exactly two kinds, labelled positive and negative by Franklin's convention. The convention is arbitrary and, as it turned out, inconvenient: the particle that actually moves in a metal, the electron, came out negative. What matters is that charges combine as signed numbers, so a net charge is a sum with cancellation allowed: q = q₁ + q₂ + q₃ + … . A speck of dust holding 10¹⁸ protons and 10¹⁸ electrons has q = 0 and behaves, from a distance, exactly as if it held nothing. Build the habit now of writing the sign into the symbol rather than carrying it in words; later, when forces are superposed, the sign does the work of a direction.

2The coulomb is enormous and e is tiny

One coulomb is (1 C)/e = 6.24 × 10¹⁸ elementary charges, which makes it a wildly oversized unit for static electricity. A rubbed rod carries a few nanocoulombs, and 1 nC is 6.24 × 10⁹ electrons — a huge count, but nothing beside the electrons already present. Take 3.0 g of copper: 0.047 mol, 2.8 × 10²² atoms, 29 electrons each, so 8.3 × 10²³ electrons carrying 1.3 × 10⁵ C, matched by as much positive charge in the nuclei. A 5 nC imbalance on that copper is a fractional miscount of 5 × 10⁻⁹ ÷ (1.3 × 10⁵) ≈ 4 × 10⁻¹⁴. Two lessons follow. Net charge is hard to build up, which is why electrostatic charges live in the nanocoulomb range. And moving charge is easy: a 1 A current pushes a whole coulomb along a wire every second, because the wire stays neutral while the electrons drift through it.

3Quantisation is a measurement, not a postulate

Nothing in the idea of charge requires it to come in lumps; experiment does. In an oil-drop cell the charge on each droplet is measured one drop at a time, and the values do not spread smoothly. They cluster on a ladder, with the differences between drops coming out as whole multiples of one common step. The practical move is to work with those differences, because a common calibration offset cancels in a difference and any true quantum has to divide every gap. Find the largest number that divides all the gaps, then confirm it by dividing it into the raw charges and checking that every quotient lands on a whole number. Two cautions. With only a handful of drops the true quantum may be half the step you found, so you need enough gaps to be sure. And since 20 May 2019 the experiment no longer measures e at all: e is defined as exactly 1.602176634 × 10⁻¹⁹ C, so the oil drop now demonstrates that charge is quantised, with the size of the quantum fixed by definition.

4Conservation is an identity with a boundary attached

Charge conservation says the algebraic sum of charge inside a closed boundary never changes. Used as a tool it is one equation: write the signed sum before, write the signed sum after, set them equal, and solve for whatever is unknown. Ionising a sodium atom gives 0 → (+e) + (−e). Beta decay of a free neutron gives 0 → (+e) + (−e) + 0, which is how you know the antineutrino must be neutral. Pair production turns one photon into an electron and a positron: 0 → (−e) + (+e). Rubbing a balloon on a wool jumper is the same identity at a different scale: 0 → (−12.0 nC) + (+12.0 nC). The word closed is doing real work here. Touch the balloon with a damp hand and charge leaks across the boundary you drew, so the sum inside is free to change — the conservation law has not failed, your boundary has.

5Charge cannot teleport, so track what crosses the surface

Conservation is stronger than a global bookkeeping rule: charge does not vanish in one place and reappear in another, it flows. The charge of a region therefore changes only by what passes through its surface, and that flow is a current: Δq = ∫ I dt, which becomes Δq = I Δt when I is steady. This is what turns a conservation statement into a number. A charged sphere leaking 2.5 μA to the air for 4.0 s loses Δq = 2.5 × 10⁻⁶ A × 4.0 s = 1.0 × 10⁻⁵ C, or 6.2 × 10¹³ electrons. Read the same equation the other way and a transfer becomes a current: a spark carrying 3.0 nC across a gap in 12 ns averages 3.0 × 10⁻⁹ C ÷ (12 × 10⁻⁹ s) = 0.25 A. The sign convention comes with it: a positive current into a region raises its charge and a positive current out lowers it, while electrons drifting in lower it, because they carry negative charge.

6Where the model stops, and how hard it has been tested

Quarks break the staircase one level down: an up quark carries +2e/3 and a down quark −e/3, so a proton (uud) is 2/3 + 2/3 − 1/3 = +1 in units of e, and a neutron (udd) is 2/3 − 1/3 − 1/3 = 0. Confinement keeps them bound inside hadrons, and searches for free fractional charge in bulk matter have found none down to fewer than about one per 10²¹ nucleons, so every charge you can isolate and measure is still N e. Two further facts are worth carrying. Charge is invariant: unlike energy or mass it does not depend on how fast its carrier moves, which is why a hydrogen atom is neutral to better than 10⁻²¹ e even though its electron moves at about 1% of the speed of light. And conservation has survived every test aimed at it — an electron decaying into a photon and a neutrino would destroy charge, and its mean life is known to exceed 6.6 × 10²⁸ years.

2

Key equations

Read the units, assumptions and limits before substituting.

Quantisation of charge

q = N e, N = 0, ±1, ±2, ±3, …

Every charge you compute must divide by e into a whole number — a one-line test on an answer.

q is the net charge in coulombs (C); N is a whole number, never a fraction

The elementary charge

e = 1.602176634 × 10⁻¹⁹ C

Fixes the step size of the staircase, and is no longer a quantity an experiment has to measure.

Exact since the 2019 SI revision, where it defines the ampere and so the coulomb

Counting the transferred electrons

N = |q| / e

Turns a nanocoulomb reading into a count you can weigh against the electrons actually available.

q in coulombs (C), e in coulombs (C), N a pure number; 1 nC ↔ 6.24 × 10⁹ electrons

Net charge of an object

q = (Nₚ − Nₑ) e

Shows that neutral means the difference is zero, not that the object holds no charge.

Nₚ protons and Nₑ electrons inside the object, both enormous, their difference tiny

Conservation in a closed system

Σq (before) = Σq (after)

Fixes the unknown charge of one product once every other charge in the reaction is known.

Signed sum over everything inside one boundary, in coulombs (C)

Charge crossing a boundary

Δq = ∫ I dt

A system's charge changes only by what flows through its surface: conservation is local, not merely global.

I in amperes (A), t in seconds (s), Δq in coulombs (C)
3

Interactive lab

Predict first. Explore the model. Compare the result.

Explore the model

0.0 nC
−4 to 4 nC; steps of 0.5.
0.0 nC
−4 to 4 nC; steps of 0.5.
1.5 ×10¹⁰
0 to 5 ×10¹⁰; steps of 0.5.

Try this. Drag the electron slider and watch the two left bars move in opposite directions while the right bar stays frozen: transfer changes who holds the charge, never how much charge there is.

Live results

CHARGE ON A
2.40 nC
CHARGE ON B
-2.40 nC
TOTAL qA + qB
0.00 nC
NEGATIVE CHARGE MOVED
2.40 nC

Results follow this lesson’s model and assumptions. Displayed values are rounded.

Interactive Physics II modelCharge ledger for two objects. A starts at 0.0 nC and B at 0.0 nC, then 1.5 × 10¹⁰ electrons — carrying 2.40 nC of negative charge — move from A to B. The left bar is q_A, the middle bar q_B, and the right bar their sum, which no setting of the electron slider can shift.closed system: qA + qB cannot changemoved: 1.5 × 10¹⁰ electrons = 2.40 nCelectrons flow A → BqA = 2.40 nCqB = −2.40 nCsum = 0.00 nC+8 nC0−8 nC
Charge ledger for two objects. A starts at 0.0 nC and B at 0.0 nC, then 1.5 × 10¹⁰ electrons — carrying 2.40 nC of negative charge — move from A to B. The left bar is qA, the middle bar qB, and the right bar their sum, which no setting of the electron slider can shift.

Predict → change one variable → check

Plan a change before running it. Every other input stays at the saved baseline.

Saved baseline. Object A starting charge: 0.0 nC; Object B starting charge: 0.0 nC; Electrons moved A → B: 1.5 ×10¹⁰

Baseline 0.0; choose −4 to 4, in steps of 0.5.
4. Compared with the saved baseline, this result will…

This experiment is kept only while this page is open. It does not change saved course progress.

4

Catch the common trap

The usual reading of “the rod became charged” is that rubbing made charge. It did not. Rod and cloth each start with enormous equal amounts of both signs, and rubbing only moves electrons across the contact: if the rod ends at −4.8 nC the cloth ends at exactly +4.8 nC, and the pair's total is still zero. The other half of the same error is hearing “neutral” as “no charge present”. A 3.0 g piece of copper holds about 1.3 × 10⁵ C of electrons and the same of protons; neutral means those two sums cancel, not that the copper is empty. Both errors cost you later, because a neutral object full of charge can still be pulled by a charged rod — impossible if neutral meant nothing was there.

5

Practice & worked examples

3 authored examples. Make an attempt, then reveal the reasoning one step at a time.

EasyExample 1

A nylon comb is drawn through dry hair and afterwards carries a charge of −8.50 nC. (a) How many surplus electrons does it hold? (b) If comb and hair were both neutral beforehand, what charge does the hair carry, and what is the total charge of the pair?

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 4 steps revealed.

MediumExample 2

Four oil drops in a Millikan-type cell are measured to carry −6.409 × 10⁻¹⁹ C, −1.1215 × 10⁻¹⁸ C, −1.6022 × 10⁻¹⁸ C and −2.2430 × 10⁻¹⁸ C. Show the data are consistent with quantised charge, extract the size of the quantum, and say how many electrons each drop holds.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

HardExample 3

The lower region of a thundercloud holds −24.0 C. One return stroke carries 18.0 C of negative charge to the ground in 75.0 μs. Find (a) the average current, (b) the number of electrons delivered, (c) the region's charge afterwards, and (d) the mass of the electrons delivered, with mₑ = 9.109 × 10⁻³¹ kg.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

6

Quick check

Select an answer and explain it before checking.

An uncharged metal sphere is touched with a negatively charged plastic rod and is left holding −3.20 nC. Which statement describes what happened?
7

Review & continue

Electric charge is the signed, conserved property of matter that comes only in whole multiples of the elementary charge e = 1.602176634 × 10⁻¹⁹ C, so any object's net charge is q = N e for some integer N — positive, negative or zero.

  • Explain the relationship without looking at the equation.
  • Check a sign, a unit and a model assumption in your working.
  • Return to the lab or worked example if a step is still unclear.

Optional supporting lessons

These chapter resources can help with earlier ideas; they are not additional required Physics II completion tasks.

Extra challenging questions

Connect several ideas, explore supplied data, and compare your reasoning with a worked solution.