
Optional unit · institution-dependent · Interactive lesson
The Ray Model & Reflection
Before any lens or curved mirror, settle what a ray is and what it does at a flat surface: angles measured from the normal and never from the surface, one law covering both a polished mirror and a matte wall, and the beam width below which rays fail.
UPII-13.01 · Lesson 1 of 8 in this unit. Position is not a completion score.Optional unit · institution-dependent. Your university may teach this optics or introductory modern-physics material separately. Follow your institution’s required sequence. Optional work is not a required completion gate.
Build the model
A ray is a wavefront normal, and a mirror returns it at the angle it arrived.
The key idea
The ray model represents light as straight lines drawn perpendicular to its wavefronts, and the law of reflection fixes what one of them does at a smooth surface: it leaves in the plane of the incident ray and the normal, on the opposite side of the normal, at the same angle.
Example. A ray meeting a flat mirror 22° from the normal leaves 22° from the normal on the other side, so the incoming and outgoing segments make 44° at the mirror and the direction of travel is turned through 180° − 44° = 136°.
The complete physical model and assumptions
Geometrical optics is a single approximation with a single consequence, and this topic is the two of them. The approximation is that the wavelength counts as zero; what it buys is a direction, since with λ negligible against every aperture in the apparatus the only thing about a wave still worth tracking is the normal to its wavefronts, and that normal is the ray. The consequence is that a boundary can then be handled by one strictly local rule. Reflection does not ask how wide the beam is, how far away the source sits, or what the surface is doing a millimetre away; it reads the normal at the single point struck and returns the ray symmetrically about it, θᵣ = θᵢ. Locality is why one law is enough for every surface — a polished plate and a sheet of paper differ in how their normals are distributed, not in the rule those normals obey — and why an image needs no separate law, since applying that rule to every ray leaving one object point already sends the reflected rays out as though from a common point behind the mirror. Locality is also what the model costs: with λ discarded, nothing left in the description remembers that light is a wave, so as soon as an aperture closes toward λ, or two paths cross where their phases matter, straight lines stop predicting where the light lands.
1Rays are wavefront normals, not thin beams
A wavefront is a surface of constant phase, and a ray is the line perpendicular to it, drawn in the direction the energy moves. Far from a small source the wavefronts are spheres and the rays are radii; a collimated beam has plane wavefronts and parallel rays. The picture is a limit, not a physical object: no experiment isolates a single ray, and trying to make one by narrowing an aperture defeats itself. It earns its keep because visible light is short — λ = 550 nm against a 5.0 mm aperture is about 9.1 × 10³ wavelengths across — so over laboratory distances the wave's spreading is invisible and light does travel in straight lines within a uniform medium. Two consequences follow at once. Rays cross without deflecting one another, so a crowded ray diagram is legitimate. And the model tracks direction only: it says where light goes, never how much of it goes there, and never with what phase it arrives.
2Huygens' construction gives the law of reflection
Take a plane wavefront meeting a plane surface with its normal at angle θᵢ. One end of the wavefront, at A, reaches the surface first; the other end still has a distance ct to travel before it lands at B. While it covers that distance, A re-emits a hemispherical wavelet that grows to radius ct. The new wavefront is the plane through B tangent to that wavelet, touching it at C. The triangle ABC and the incident triangle are right angled, share the hypotenuse AB, and have equal opposite sides ct, so they are congruent and the angles at A and B match: θᵣ = θᵢ. The wavelet is centred on the surface, so its tangent plane puts the reflected ray in the plane of the incident ray and the normal, on the opposite side of it. Read the angles from the normal, never from the surface: a ray arriving 28° from the normal leaves 28° from the normal, its direction of travel turned through 180° − 56° = 124°.
3One law, two appearances: specular and diffuse
A rough surface does not break the law of reflection; it applies the law independently on each microscopic facet, and the facets have different normals, so the reflected rays fan out. What decides which behaviour you see is the height of the roughness against the wavelength. The Rayleigh criterion puts the boundary at Δh ≈ λ/(8 cos θᵢ): at λ = 550 nm and normal incidence a surface must be flat to 69 nm to act as a mirror, which is why float glass with a few nanometres of waviness returns a sharp image while a matte wall with 10 μm of texture, about 150 times the limit, returns none. The cos θᵢ matters too. Take a paper surface with Δh = 0.60 μm: at normal incidence the limit is 69 nm and it looks matte, but at θᵢ = 85° the limit rises to 550 nm ÷ (8 × 0.0872) = 789 nm, above its roughness, and the same paper throws a glossy sheen. That is the low-sun glare off a dry road.
4Where a plane mirror puts the image
Take an object point O a perpendicular distance d in front of the mirror and draw any two rays from it. Each reflects with θᵣ = θᵢ about the local normal, and the two reflected rays diverge, so no light converges anywhere. Extend them backwards and they meet at a single point I on the normal through O, a distance d behind the mirror; the two right triangles sharing the mirror line are congruent, which fixes d′ = d whichever pair of rays you chose. The image is virtual: put a screen at I and nothing appears on it. The eye cannot tell, because it samples only the diverging cone that reaches it. Stand 1.8 m from a wall mirror and your eyes accommodate as though the object were 3.6 m away, and what they see is erect and life-size, m = +1. The reversal people notice is along the normal rather than sideways: the mirror swaps front and back, which is why the image of a right hand is a left hand.
5Rotate the mirror and the ray turns twice as fast
Hold the incident ray fixed and rotate the mirror through α about an axis lying in its surface, perpendicular to the plane of incidence. The normal rotates with the mirror, through the same α, so the angle of incidence changes by α. The reflected ray must stay at that angle on the other side of the normal, so it moves twice over: once because the normal moved through α, and again because its angle from that normal changed by α. The total is 2α, and the original angle of incidence never enters, so the factor of two is exact rather than a small-angle approximation. That is the optical lever. Send the reflected beam onto a scale a distance L away, arranged so the beam meets the scale perpendicularly, and the spot moves L tan(2α): with L = 1.50 m a mirror rotation of 0.25° shows as 1.50 × tan 0.50° = 13.1 mm. Galvanometers, atomic-force-microscope cantilevers and laser scanners all live on this factor of two.
6The scale at which rays stop being honest
The ray model is the assumption that apertures are huge compared with the wavelength. Push the other way and it fails in a measurable, predictable manner: light passing through a width a spreads through a half-angle of roughly λ/a. At λ = 550 nm a 2.0 mm beam carries θ ≈ 2.8 × 10⁻⁴ rad, which is 0.28 mm of spreading per metre — nothing against a 2.0 mm beam on a benchtop, so ray tracing is safe. Shrink the aperture to 20 μm and the same estimate gives 2.8 × 10⁻² rad, or 28 mm per metre: the beam is now a fan and no straight line describes it. The discarded phase returns whenever two beams overlap as well, since rays are drawn as though they ignore each other while real light interferes. So trace rays for mirrors, lenses and instrument layouts, and abandon them for slits, thin films and any question about resolution.
Key equations
Read the units, assumptions and limits before substituting.
Law of reflection
θᵣ = θᵢ
Fixes the outgoing direction from the local normal alone, so it can be applied facet by facet on any surface.
θᵢ and θᵣ are measured from the surface normal, in ° or rad; the two rays and the normal share one planeDeviation at one reflection
δ = 180° − 2θᵢ
Grazing incidence barely bends the ray; normal incidence sends it straight back, δ = 180°.
δ is the angle the direction of travel is turned through, in ° (or rad as π − 2θᵢ)Rotate the mirror, turn the ray twice
Δ = 2α
The optical lever: a spot on a scale L metres away moves L tan(2α), so 0.25° of mirror reads as 13 mm at 1.50 m.
α is the mirror's rotation about an axis in its surface, Δ the reflected ray's turn, both in ° or radImage in a plane mirror
d′ = d
Each point maps along its own normal, so the image is virtual, erect and life-size, m = +1.
d is the object's perpendicular distance in front of the mirror plane and d′ the image's behind it, in mRayleigh smoothness criterion
Δh < λ / (8 cos θᵢ)
At λ = 550 nm and normal incidence a surface must be flat to 69 nm before it reflects like a mirror.
Δh is the peak-to-valley roughness in m, λ the wavelength in m, θᵢ the angle of incidenceWhere the ray model runs out
θspread ≈ λ / a
Rays are safe while a ≫ λ: a 2.0 mm beam spreads 0.28 mm per metre, a 20 μm beam spreads 28 mm per metre.
a is the beam width or aperture in m, λ the wavelength in m, θspread the half-angle in radInteractive lab
Predict first. Explore the model. Compare the result.
Explore the model
Try this. Leave the incident ray alone and drag the mirror tilt from 0° to 10°: the normal moves 10°, the angle of incidence drops by 10°, and the reflected ray swings 20° off the dashed reference — twice the mirror's own rotation.
Live results
- ANGLE OF INCIDENCE
- 45 °
- ANGLE OF REFLECTION
- 45 °
- ANGLE TO MIRROR FACE
- 45 °
- SWING FROM α = 0
- 0 °
Results follow this lesson’s model and assumptions. Displayed values are rounded.
Predict → change one variable → check
Plan a change before running it. Every other input stays at the saved baseline.
Saved baseline. Incident ray angle θ₀: 45 °; Mirror tilt α: 0 °
This experiment is kept only while this page is open. It does not change saved course progress.
Catch the common trap
The commonest wreck here is measuring angles from the mirror surface. A ray striking 20° from the surface has θᵢ = 70°, not 20°, and θᵣ = 70° with it; use the surface angle instead and the deviation comes out as 140° where it should be 40°, with every later step inheriting the error. The second wreck is thinking you can see more of yourself by stepping back from a wall mirror. You cannot. The ray from your feet reaches your eye off a point exactly halfway up from feet to eye level, and the ray from the top of your head off a point halfway between eye level and your crown, and neither height depends on how far away you stand, because the image retreats exactly as far as you do. The strip of glass you actually use always spans half your height and always sits in the same place on the wall.
Practice & worked examples
3 authored examples. Make an attempt, then reveal the reasoning one step at a time.
EasyExample 1
A laser ray strikes a flat horizontal mirror, making 34° with the mirror surface. (a) Find the angle of incidence, the angle of reflection, and the angle through which the ray's direction of travel is turned. (b) The mirror is swapped for a metal plate of the same shape whose peak-to-valley roughness is 1.2 μm. Taking λ = 550 nm, decide whether the reflection is still specular.
Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.
0 of 5 steps revealed.
- Optical angles are measured from the normal, and the normal is perpendicular to the surface, so θᵢ = 90° − 34° = 56°.
- The law of reflection gives θᵣ = θᵢ = 56°, on the other side of the normal and in the same plane as the incident ray and the normal.
- The direction of travel is turned through δ = 180° − 2θᵢ = 180° − 112° = 68°. Check it another way: the incoming and outgoing segments make 180° − 34° − 34° = 112° at the mirror, and 180° − 112° = 68°.
- Specular reflection needs Δh < λ/(8 cos θᵢ) = 550 nm ÷ (8 × cos 56°) = 550 ÷ 4.47 = 123 nm.
- The plate's 1.2 μm is 1200 nm, about 9.8 times that limit, so its facet normals scatter the light: the reflection is diffuse, even though every facet still obeys θᵣ = θᵢ exactly.
Answer. θᵢ = θᵣ = 56° and the deviation is 68°; the roughened plate is about ten times too rough at 550 nm (limit 123 nm), so it reflects diffusely.
MediumExample 2
A small plane mirror is glued to the suspension of a galvanometer. A laser beam reflects from it onto a straight scale 2.40 m away, mounted so that the reflected beam meets the scale perpendicularly at the zero mark. (a) How far along the scale does the spot move when the mirror turns through 0.42°? (b) If the spot can be read to 0.5 mm, what is the smallest mirror rotation the instrument can detect?
Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.
0 of 5 steps revealed.
- Rotating the mirror by α swings the reflected beam by 2α, so the beam swings 2 × 0.42° = 0.84°.
- The beam leaves perpendicular to a scale L = 2.40 m away, so the spot's displacement is d = L tan(2α).
- d = 2.40 m × tan 0.84° = 2.40 × 0.014662 = 0.03519 m = 35.2 mm. A rotation under half a degree has been magnified into a shift you can read with a ruler.
- Invert for the smallest detectable rotation: 2α = arctan(0.0005 m ÷ 2.40 m) = arctan(2.083 × 10⁻⁴) = 2.083 × 10⁻⁴ rad, so α = 1.04 × 10⁻⁴ rad.
- In degrees that is 5.97 × 10⁻³°, about 21 arcseconds. Doubling L halves it, which is why optical levers are given long throws.
Answer. The spot moves 35.2 mm; the smallest detectable mirror rotation is 1.04 × 10⁻⁴ rad, which is 5.97 × 10⁻³° or about 21 arcseconds.
HardExample 3
Two plane mirrors meet along a common edge at right angles, and a ray travels in the plane perpendicular to that edge, striking one mirror and then the other. (a) Show that the emerging ray is exactly antiparallel to the incoming one whatever the first angle of incidence. (b) The joint is then misaligned so the mirrors meet at 88.5°. Find how far the return is from antiparallel, and the sideways miss on a target 100 m away.
Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.
0 of 5 steps revealed.
- Let the mirrors meet at φ and the ray strike the first at θ₁, the second at θ₂. The triangle made by the two strike points and the vertex has angle φ at the vertex and angles 90° − θ₁ and 90° − θ₂ at the mirrors, so φ + (90° − θ₁) + (90° − θ₂) = 180°, giving θ₁ + θ₂ = φ.
- Each reflection turns the direction of travel by 180° − 2θ, and both turns run the same way round, so the total is (180° − 2θ₁) + (180° − 2θ₂) = 360° − 2(θ₁ + θ₂) = 360° − 2φ. Only φ survives; θ₁ has cancelled.
- With φ = 90° the total turn is 360° − 180° = 180°, an exact reversal for every θ₁. That is the corner reflector used in cycle reflectors and lunar ranging.
- With φ = 88.5° the total turn is 360° − 177° = 183°, which overshoots a straight reversal by 3.0°, so the emerging ray is 3.0° from antiparallel. Check with θ₁ = 35°: θ₂ = 88.5° − 35° = 53.5°, and the turns are 180° − 70° = 110° and 180° − 107° = 73°, totalling 183°.
- The error is 2 × 1.5° = 3.0°, twice the misalignment, exactly as for one rotated mirror. Over 100 m the return misses by 100 m × tan 3.0° = 5.24 m.
Answer. At 90° the return is antiparallel for every θ₁. At 88.5° it is 3.0° off antiparallel, twice the 1.5° misalignment, and misses a target 100 m away by 5.2 m.
Quick check
Select an answer and explain it before checking.
Review & continue
The ray model represents light as straight lines drawn perpendicular to its wavefronts, and the law of reflection fixes what one of them does at a smooth surface: it leaves in the plane of the incident ray and the normal, on the opposite side of the normal, at the same angle.
- Explain the relationship without looking at the equation.
- Check a sign, a unit and a model assumption in your working.
- Return to the lab or worked example if a step is still unclear.
Optional supporting lessons
These chapter resources can help with earlier ideas; they are not additional required Physics II completion tasks.