Skip to main content

Physics II course sequence · Interactive lesson

Charging by Friction, Contact & Induction

Three ways to leave an object charged, and one rule under all of them: electrons change hands. Learn to say which way they went, how many went, and what sign each object is left holding — then check that the books balance.

UPII-01.03 · Lesson 3 of 8 in this unit. Position is not a completion score.
Starting model: Charging by Friction, Contact & InductionA bead carrying −6.0 nC is held d = 12 cm from the centre of a metal sphere of radius 4.0 cm on an insulating post, drawn to scale; the bead is withdrawn at step 4 and the wire to earth is shown only at step 2. Below, a signed ledger gives the charge on the bead, the sphere and the earth, positive above the line. At step 2 the sphere holds 2.00 nC and the earth -2.00 nC; the three always sum to −6.0 nC.step 2 of 4bead −6.0 nC at d = 12 cmmetal sphere, R = 4.0 cmearthpositive is above the linebeadsphereearth
Start with a picture. Change the model in the lab below.
1

Build the model

Nothing is created. Electrons change owner, and the books must balance.

The key idea

Charging by friction, contact and induction are three ways of moving electrons between objects: rubbing transfers them at a surface, touching shares them between conductors, and induction uses a nearby charge plus a path to earth to strand a charge of the opposite sign.

Example. A polythene rod rubbed with wool ends at −2.0 × 10⁻⁸ C: 1.2 × 10¹¹ electrons have crossed onto the rod, the wool is left at +2.0 × 10⁻⁸ C, and the pair together is still exactly neutral.

The complete physical model and assumptions

No process in this section creates charge; each one moves electrons and leaves a deficit behind. Rubbing two dissimilar insulators presses their surfaces into intimate contact at countless points, and because the two materials hold their outer electrons with different tenacity a thin layer of electrons crosses and stays where it lands, so the two objects separate with equal and opposite charges. Touching a charged conductor to a neutral one is a different mechanism: the mobile electrons of a metal redistribute until both bodies sit at one common potential, so the charge is shared and both end with the same sign. Induction is different again. A charge held nearby polarizes a conductor without touching it; opening a path to earth lets the unwanted sign leave, and breaking that path before withdrawing the inducing charge strands a charge opposite in sign to it. Throughout, two ledgers must balance: the total charge of the isolated system, and the whole number of electrons N = |Δq|/e. The model runs out where charge stops staying put — humid air leaks it away in seconds, and no surface holds more than about 2.7 × 10⁻⁵ C m⁻² before the air beside it breaks down.

1Rubbing hands electrons over, it does not make them

Press two dissimilar materials together and their outermost electrons feel two different pulls; at every point of genuine contact a few electrons cross to the material that grips them harder and stay there. Rubbing does not create that transfer, it multiplies it, because two rough surfaces sliding over one another meet at far more points than two surfaces merely laid together. The triboelectric series lists materials in the order they surrender electrons — hair and wool near the giving end, polythene and PTFE near the taking end — so wool rubbed on polythene leaves the polythene negative and the wool equally positive. The amounts are tiny in electron terms and large in electrostatic ones. Take the rod above at −2.0 × 10⁻⁸ C: a 25 g polythene rod contains about 8.6 × 10²⁴ electrons, so the 1.2 × 10¹¹ that crossed are about 1.5 parts in 10¹⁴ of them. Because polythene is an insulator, those electrons stay in the patch where they landed instead of spreading over the rod.

2Contact charging shares, and size sets the share

A metal behaves differently, because its conduction electrons roam the whole body. Touch a charged conductor to a neutral one and the pair becomes a single conductor; electrons flow until it reaches one common potential, and both objects come away carrying the same sign as the charged one. For two identical spheres symmetry does the work — whatever one has the other must have — so the total divides in half, and every further touch halves again. For unequal spheres size sets the split. Keep them far apart, join them with a thin wire, and each sits at V = kq/R, so equal potentials give q ∝ R. A sphere of radius 5.0 cm carrying +14 nC, wired to a neutral sphere of radius 2.0 cm, ends at +10 nC while the small one takes +4.0 nC. Notice that the larger share went to the larger sphere, not to the one that started charged: the split is decided by radius alone. Watch what the electrons did — the big sphere fell from +14 nC to +10 nC, so 2.5 × 10¹⁰ electrons ran from the small neutral sphere onto it. Why both must reach one potential is proved in the unit on electric potential; the ratio is usable before then.

3Induction: the order of operations decides the sign

Charging by induction never touches the object being charged. Hold a rod at −6.0 nC beside a metal sphere on an insulating stand. Step one: the rod's field pushes the sphere's conduction electrons to the far side, leaving the near side short of them. The net charge is still zero, so nothing has been won yet. Step two: run a wire from the sphere to earth. The electrons crowded on the far side are now free to leave, and they go, because earth accepts them. Step three: remove the wire while the rod is still in place. The sphere is now short of electrons with no route back to earth. Step four: withdraw the rod, and the positive charge left behind spreads over the whole surface. The sphere is charged, its sign is opposite to the rod's, and the rod is untouched. Swap steps three and four and you get nothing: withdraw the rod first and the electrons simply climb back up the wire, leaving a neutral sphere. The sequence is the physics.

4What the earth actually does

Earth is not a drain that empties things. It is a reservoir so large that charge entering or leaving it does not shift its potential. Which way charge moves through a grounding wire is decided by the field at the grounded object, never by the wire itself. A negative rod nearby drives electrons down into the earth and leaves the object positive; a positive rod draws electrons up out of the earth and leaves it negative. This is also why a grounded conductor sitting near a charge is not neutral. Grounding does not make the field inside the metal vanish — that is already true of any conductor in electrostatic equilibrium, charged or not. What the wire fixes is the potential: the conductor takes on exactly the charge that holds it at the earth's potential, and how much that is depends on the geometry. For a point charge q at distance d from the centre of a grounded sphere of radius R, the charge drawn from earth is −qR/d, a result the method of images will prove in a later unit. With q = −6.0 nC, R = 4.0 cm and d = 12 cm the sphere takes +2.0 nC, and at d = 24 cm only +1.0 nC. The nearer the inducing charge when you cut the wire, the more you keep.

5Predict the sign before you compute anything

Three questions in order settle the sign of every problem in this topic. Did the charged object touch the target? If it did, this is contact charging: the target ends with the same sign as the charger, and the charger itself ends with less charge than it started with. If it did not, was there a path to earth that was broken while the charged object was still present? If so, this is induction: the target ends with the opposite sign, the charger is unchanged, and the charge was traded with the earth. If neither, the target was only polarized, and it ends neutral however dramatic it looked while the rod was near. Run the four-step sequence above through these questions, at the 12 cm spacing used earlier, and the answers appear before any arithmetic — sphere +2.0 nC, rod still −6.0 nC, earth −2.0 nC, the three summing to −6.0 nC, which is what the system held before anything was done to it. When a calculation disagrees with that ledger, the calculation is wrong.

6Where the charging model runs out

Four limits matter. Charge does not stay put: on a humid day a film of water on an insulator carries it away in seconds, which is why these demonstrations fail in August and work in January. There is also a hard ceiling, because a surface cannot exceed σₘₐₓ = ε₀Eb, and with Eb = 3.0 × 10⁶ V m⁻¹ for dry air that is 2.7 × 10⁻⁵ C m⁻²; a charged face of 1.0 × 10⁻² m² therefore carries at most 2.7 × 10⁻⁷ C, which is why these demonstrations deal in nanocoulombs. The triboelectric series is a rule of thumb rather than a law — its order shifts with roughness, contamination and humidity, and some pairs reverse outright. And the sharing results assume ideal conductors held far apart; two spheres in contact are close enough to distort each other's charge, so q ∝ R is a sound estimate rather than an exact answer. What survives all four is the bookkeeping: whatever leaves one object arrives somewhere else, in whole electrons.

2

Key equations

Read the units, assumptions and limits before substituting.

Conservation in a transfer

q₁′ + q₂′ = q₁ + q₂

Turns the question of how much moved into one subtraction: a change Δq on one body is −Δq on the other.

Charges in coulombs (C) for an isolated pair; the primes mark the values after the process.

Electrons behind the charge

N = |Δq| / e, with e = 1.602 × 10⁻¹⁹ C

Converts a measured charge into the number of electrons that actually changed owner.

Δq in coulombs, N a whole number of electrons — a transfer is never a fraction of one.

Contact sharing, identical spheres

q₁′ = q₂′ = (q₁ + q₂) / 2

Fixes both sign and size after a touch, and halves what is left with every repeat.

Charges in coulombs, for two identical isolated conducting spheres touched once and separated.

Contact sharing, unequal spheres

qᵢ = (q₁ + q₂) Rᵢ / (R₁ + R₂)

Equal potentials, not equal charges: the larger sphere always takes the larger share.

Radii in metres; spheres far apart on a thin wire, so each sits at V = kq/R with k = 1/(4πε₀).

Polarization moves nothing net

qₙₑₐᵣ + qfar = 0

Says why induction needs a ground: with no path out, nothing leaves and the net stays zero.

Induced charges in coulombs on an isolated, ungrounded conductor of any shape.

Ceiling on surface charge

σₘₐₓ = ε₀ Eb ≈ 2.7 × 10⁻⁵ C m⁻²

Caps what any charging process can leave behind: past it the air sparks the charge away.

ε₀ = 8.85 × 10⁻¹² C² N⁻¹ m⁻²; dry air breaks down at Eb ≈ 3.0 × 10⁶ V m⁻¹.
3

Interactive lab

Predict first. Explore the model. Compare the result.

Explore the model

2
1 to 4; steps of 1.
6.0 nC
1 to 10 nC; steps of 0.5.
12 cm
8 to 24 cm; steps of 1.

Try this. Set d = 8 cm and walk step 1 → 2 → 3 → 4: the sphere ends at +{q/2|2} nC although the bead never touched it. Repeat at d = 24 cm and the keeper is a third as large — what you strand is fixed by the gap at the instant the wire is cut.

Live results

NET ON SPHERE
2.00 nC
NET ON EARTH
-2.00 nC
ELECTRONS TO EARTH
12.48 ×10⁹
BEAD + SPHERE + EARTH
-6.0 nC

Results follow this lesson’s model and assumptions. Displayed values are rounded.

Interactive Physics II modelA bead carrying −6.0 nC is held d = 12 cm from the centre of a metal sphere of radius 4.0 cm on an insulating post, drawn to scale; the bead is withdrawn at step 4 and the wire to earth is shown only at step 2. Below, a signed ledger gives the charge on the bead, the sphere and the earth, positive above the line. At step 2 the sphere holds 2.00 nC and the earth -2.00 nC; the three always sum to −6.0 nC.step 2 of 4bead −6.0 nC at d = 12 cmmetal sphere, R = 4.0 cmearthpositive is above the linebeadsphereearth
A bead carrying −6.0 nC is held d = 12 cm from the centre of a metal sphere of radius 4.0 cm on an insulating post, drawn to scale; the bead is withdrawn at step 4 and the wire to earth is shown only at step 2. Below, a signed ledger gives the charge on the bead, the sphere and the earth, positive above the line. At step 2 the sphere holds 2.00 nC and the earth −2.00 nC; the three always sum to −6.0 nC.

Predict → change one variable → check

Plan a change before running it. Every other input stays at the saved baseline.

Saved baseline. Step in the sequence: 2; Bead charge magnitude: 6.0 nC; Bead distance from centre: 12 cm

Baseline 2; choose 1 to 4, in steps of 1.
4. Compared with the saved baseline, this result will…

This experiment is kept only while this page is open. It does not change saved course progress.

4

Catch the common trap

The commonest error is to treat the inducing rod as a supply. In charging by induction the rod never touches the sphere and never loses a single electron: test it on an electroscope afterwards and it reads exactly what it read before. The electrons that move come from the earth, through the grounding wire, and they move in the direction the rod's field pushes them — away from a negative rod, towards a positive one. That is why the sphere is left with the sign opposite to the rod's, and why induction is the one process here whose final sign is not the charger's. Contact charging is the mirror image: the rod does give up charge, and the object it touched ends with the rod's own sign. Decide which process happened before you assign any sign.

5

Practice & worked examples

3 authored examples. Make an attempt, then reveal the reasoning one step at a time.

EasyExample 1

A glass rod is rubbed with a silk cloth and afterwards carries +4.8 nC. Say which way the electrons moved, how many of them moved, and what charge the silk is left with. Take e = 1.602 × 10⁻¹⁹ C.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 4 steps revealed.

MediumExample 2

Two isolated conducting spheres stand far apart on insulating posts. Sphere A has radius 3.0 cm and carries +12 nC; sphere B has radius 9.0 cm and is neutral. A long thin wire joins them briefly and is then removed. Find the final charge on each, and the number of electrons that crossed the wire and in which direction.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

HardExample 3

A metal sphere of radius 2.0 cm on an insulating stand is neutral. A rod at −6.0 nC is brought near, the sphere is earthed for a moment while 2.5 × 10¹⁰ electrons leave it, the wire is removed, and then the rod is withdrawn. (a) Find the final charge on the sphere and on the rod. (b) It is then touched to an identical neutral sphere and separated: find each charge. (c) Compare (a) with the most it could hold in dry air, where σₘₐₓ = ε₀Eb and Eb = 3.0 × 10⁶ V m⁻¹.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

6

Quick check

Select an answer and explain it before checking.

A metal sphere on an insulating stand starts neutral. A rod carrying −8.0 nC is held close to it but never touches it. While the rod is held in place a wire is run briefly from the sphere to earth and then removed, and only afterwards is the rod taken away. What charge is the sphere left with?
7

Review & continue

Charging by friction, contact and induction are three ways of moving electrons between objects: rubbing transfers them at a surface, touching shares them between conductors, and induction uses a nearby charge plus a path to earth to strand a charge of the opposite sign.

  • Explain the relationship without looking at the equation.
  • Check a sign, a unit and a model assumption in your working.
  • Return to the lab or worked example if a step is still unclear.

Optional supporting lessons

These chapter resources can help with earlier ideas; they are not additional required Physics II completion tasks.

Extra challenging questions

Connect several ideas, explore supplied data, and compare your reasoning with a worked solution.