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Physics II course sequence · Interactive lesson

Coulomb's Law

Every electrostatic force you will ever compute is this one law, used once or used a million times. Get three things right here — how big the force is, the line it acts along, and which way along that line — and most of what follows is bookkeeping.

UPII-01.04 · Lesson 4 of 8 in this unit. Position is not a completion score.
Starting model: Coulomb's LawTwo point charges on a horizontal line: q₁ = 5 nC at the left, q₂ = -3 nC a distance r = 6.0 cm to its right, each with a force arrow along that line. The arrows are equal in length and opposite in direction, pointing apart when q₁q₂ = -15 nC² is positive and together when it is negative. Each feels 37.45 µN; the curve below plots that force against r.The force pair on the line joining two point chargessign(q₁q₂) = −1 +1 pushes apart, −1 pulls togetherq₁ = 5 nCq₂ = −3 nCr = 6.0 cmF = 37.45 µN on each charge, equal and oppositeF / µNseparation r: 4 cm to 10 cm, F ∝ 1/r²
Start with a picture. Change the model in the lab below.
1

Build the model

One line, one product of charges, one inverse square.

The key idea

Coulomb's law says that two point charges at rest push or pull each other along the line joining them, with a force proportional to the product of their charge magnitudes and inversely proportional to the square of their separation.

Example. Two 1.0 nC charges 1.0 cm apart feel 8.988 × 10⁹ × (1.0 × 10⁻⁹)² ÷ (0.010)² = 9.0 × 10⁻⁵ N, or 90 µN, each. Move them to 2.0 cm apart and it is 22 µN, a quarter as much.

The complete physical model and assumptions

Coulomb's law is an experimental result with three separate claims folded into one line. The force between two charges at rest acts along the straight line joining them; its size is proportional to the product of the two charge magnitudes; and it falls off as the inverse square of the separation, F = k|q₁||q₂|/r². Direction is then settled by a single rule — like signs push apart, unlike signs pull together — and the vector form F₂₁ = (kq₁q₂/r²)r̂₂₁ encodes that rule by letting the signed product flip the unit vector. Because the expression is symmetric in q₁ and q₂, the two charges always feel forces of equal magnitude and opposite direction whatever the ratio of their charges: Newton's third law is built in, not bolted on. The law is written for point charges, so every use of it is an approximation. It is exact for two spheres whose charge is spread uniformly and stays put, excellent whenever the separation is much larger than the bodies, and wrong in a predictable direction once they are close enough to rearrange each other's charge. And it is electrostatics: set a charge moving and the force from it arrives late, with magnetism alongside.

1What the law actually claims

It is worth pulling the law apart into its three separate experimental claims, because each is tested differently and each fails differently. Claim one is geometric: the force on a charge held at rest lies along the straight line to the other charge, with no sideways component at all, so the direction of every term in a problem is fixed before any arithmetic begins. Claim two is linearity in charge: multiply either charge by a factor and the force scales by that same factor, which is why only the product |q₁||q₂| ever appears. Claim three is the exponent: the force falls as 1/r², with r measured centre to centre and not between the surfaces. Coulomb himself got the exponent from a torsion balance in 1785, reading the twist of a fine wire as he moved two charged pith balls. Modern tests never measure a force at all — they hunt for an electric field inside a closed charged conductor, which is exactly zero only if the exponent is exactly 2, and they bound any departure from 2 to about one part in 10¹⁶.

2The coulomb is huge, and so is k

Write k = 1/(4πε₀) = 8.988 × 10⁹ N m² C⁻², with ε₀ = 8.854 × 10⁻¹² C² N⁻¹ m⁻². The 4π is not decoration; it belongs to the surface area of a sphere, and it is parked here so that it cancels later when you meet Gauss's law. The sheer size of k is telling you that the coulomb is an enormous unit of charge. Two 1 C point charges 1 m apart would push each other with 9.0 × 10⁹ N, the weight of some nine hundred thousand tonnes. Nothing on a bench comes close: raise both charges to 10 nC and set them 5.0 cm apart and the push is still only 3.6 × 10⁻⁴ N, far too small to see without a torsion fibre. The same constant sets the contrast with gravity. In a hydrogen atom, with the electron 5.29 × 10⁻¹¹ m from the proton, the electric attraction is 8.24 × 10⁻⁸ N while the gravitational attraction between them is 3.6 × 10⁻⁴⁷ N, smaller by 2.3 × 10³⁹. Gravity rules the sky only because bulk matter is so nearly neutral that its charges cancel.

3Signs carry direction, magnitudes carry size

There are two ways to run a Coulomb calculation, and mixing them is where marks are lost. The safe route for hand work is to feed absolute values into F = k|q₁||q₂|/r², get a positive number, and decide the direction separately by inspection: like signs repel, unlike signs attract, and the force lies along the joining line. The formal route keeps the signs. Write F₂₁ = (kq₁q₂/r²)r̂₂₁, where F₂₁ is the force on charge 2 from charge 1 and r̂₂₁ is the unit vector pointing from charge 1 towards charge 2. If q₁q₂ is positive the force on charge 2 runs along r̂₂₁, away from charge 1; if q₁q₂ is negative the whole vector reverses and points back at charge 1. Run it on a one-dimensional case to watch the machinery bite: put q₁ = −3.0 nC at x = 0 and q₂ = +2.0 nC at x = +4.0 cm. Here r̂₂₁ = (+1, 0) and q₁q₂ = −6.0 × 10⁻¹⁸ C², a negative product, so F₂₁ points along −x̂, back towards the origin, which is the attraction the opposite signs demand. Its size is 8.988 × 10⁹ × (3.0 × 10⁻⁹)(2.0 × 10⁻⁹) ÷ (0.040)² = 3.4 × 10⁻⁵ N, and the magnitude route returns that same 3.4 × 10⁻⁵ N with the direction supplied by inspection. The two routes must always agree; what they must never do is both contribute a minus sign.

4Inverse square: reach for a ratio

Once you have one force at one separation, stop recomputing from scratch. The constant and both charges cancel in a ratio: F₂/F₁ = (r₁/r₂)². If a fixed pair of charges exerts 45 µN at 6.0 cm, then at 15 cm it exerts 45 × (6.0/15)² = 45 × 0.16 = 7.2 µN, and no value of k or q was needed. Changes to the charges multiply in independently: double one charge and triple the separation and the force becomes 2 × (1/3)² = 2/9 of what it was. The same structure appears as a straight line on a log-log plot. Taking logarithms of F = kq₁q₂r⁻² gives ln F = ln(kq₁q₂) − 2 ln r, so a graph of ln F against ln r has gradient exactly −2 and an intercept that measures the charge product. That is how force-against-separation data are really tested: the gradient checks the exponent, and it does so without knowing either charge.

5Equal forces, unequal motion

The symmetry is worth looking at directly. Coulomb's law contains the product q₁q₂ and a single separation r, and neither of those changes when you swap the labels 1 and 2, so the law is incapable of returning unequal forces: Newton's third law comes out of it as a theorem rather than going in as an extra assumption. What the symmetry does not control is the motion, because acceleration is F/m and nothing obliges the two masses to match. Take the hydrogen atom again. That same 8.24 × 10⁻⁸ N acts on the proton and on the electron, yet the electron accelerates at 9.1 × 10²² m s⁻² while the proton manages only 4.9 × 10¹⁹ m s⁻². The ratio of those accelerations is 1836, exactly the proton-to-electron mass ratio, which is why the standard picture has the electron sweeping around a proton that barely stirs. Read a Coulomb answer as one number shared by two bodies, then hand it to F = ma twice.

6When is a real object a point charge?

The law is written for points, so ask every time whether the objects qualify. Two spheres whose charge is spread uniformly and held in place act exactly like points at their centres, at any separation, by the same shell argument that lets you treat the Earth's gravity as though all its mass sat at the centre. Conductors are the awkward case, because each sphere's charge is free to move: the near faces draw together and the far faces retreat, so each sphere polarises the other. For conducting spheres of radius a at separation r carrying charges of comparable size, the leading fractional correction is about 4(a/r)³, and it always acts the same way — extra attraction, or less repulsion, never more. Two 5.0 mm spheres 40 mm apart are off by about 0.8%, small enough to ignore in a teaching lab; bring them to 15 mm apart and that leading term alone is 15%, with higher terms on top of it. Push two like-charged conductors close enough and induction can even turn the repulsion into an attraction, which the point model can never reproduce. A working rule is r ≥ 10a, which holds the leading term under half a percent — and the model assumes the charges are at rest, since moving charges bring magnetic forces and a signal delay Coulomb's law knows nothing about.

2

Key equations

Read the units, assumptions and limits before substituting.

Magnitude of the Coulomb force

F = k |q₁| |q₂| / r²

Gives the size of the push or pull; signs are deliberately left out and the direction read off separately.

q₁ and q₂ in coulombs (C), r in metres (m), F in newtons (N)

The Coulomb constant

k = 1/(4πε₀) = 8.988 × 10⁹ N m² C⁻²

Sets the scale of electrostatics: two charges of 1.0 µC, a realistic laboratory amount, repel with 9.0 × 10⁻³ N at 1.0 m.

ε₀ = 8.854 × 10⁻¹² C² N⁻¹ m⁻², the permittivity of free space

Vector form, force on charge 2

F₂₁ = (k q₁ q₂ / r²) r̂₂₁

One line gives size and direction at once: a positive product sends the force along r̂₂₁, a negative product reverses it.

F₂₁ is the force on charge 2 from charge 1; r̂₂₁ points from 1 towards 2; q₁ and q₂ keep their signs

The third-law pair

F₁₂ = −F₂₁

A 5 nC charge and a 1 nC charge feel exactly the same force size; only their accelerations differ.

equal magnitudes, opposite directions, both along the line joining the two charges

Inverse-square scaling

F₂/F₁ = (r₁/r₂)²

Triple the separation and the force falls to a ninth, without touching k or either charge.

same two charges at separations r₁ and r₂, in any one unit of length; k and the charges cancel

Electric force against gravity

Fₑ/Fg = k |q₁| |q₂| / (G m₁ m₂)

For two protons this is 1.24 × 10³⁶ at every separation, which is why gravity is invisible inside an atom.

both forces are inverse-square, so r cancels; G = 6.674 × 10⁻¹¹ N m² kg⁻²
3

Interactive lab

Predict first. Explore the model. Compare the result.

Explore the model

5 nC
−5 to 5 nC; steps of 2.
−3 nC
−5 to 5 nC; steps of 2.
6.0 cm
4 to 10 cm; steps of 0.5.

Try this. Drag r from 4 cm to 8 cm and watch both arrows shrink to a quarter, not a half; then flip the sign of q₂ and see the arrows reverse while their lengths do not change at all.

Live results

FORCE ON EACH F
37.45 µN
PRODUCT q₁q₂
-15 nC²
SIGN OF q₁q₂
-1
F IF r IS DOUBLED
9.36 µN

Results follow this lesson’s model and assumptions. Displayed values are rounded.

Interactive Physics II modelTwo point charges on a horizontal line: q₁ = 5 nC at the left, q₂ = -3 nC a distance r = 6.0 cm to its right, each with a force arrow along that line. The arrows are equal in length and opposite in direction, pointing apart when q₁q₂ = -15 nC² is positive and together when it is negative. Each feels 37.45 µN; the curve below plots that force against r.The force pair on the line joining two point chargessign(q₁q₂) = −1 +1 pushes apart, −1 pulls togetherq₁ = 5 nCq₂ = −3 nCr = 6.0 cmF = 37.45 µN on each charge, equal and oppositeF / µNseparation r: 4 cm to 10 cm, F ∝ 1/r²
Two point charges on a horizontal line: q₁ = 5 nC at the left, q₂ = −3 nC a distance r = 6.0 cm to its right, each with a force arrow along that line. The arrows are equal in length and opposite in direction, pointing apart when q₁q₂ = −15 nC² is positive and together when it is negative. Each feels 37.45 µN; the curve below plots that force against r.

Predict → change one variable → check

Plan a change before running it. Every other input stays at the saved baseline.

Saved baseline. Charge q₁ at the left: 5 nC; Charge q₂ on the right: −3 nC; Separation r: 6.0 cm

Baseline 5; choose −5 to 5, in steps of 2.
4. Compared with the saved baseline, this result will…

This experiment is kept only while this page is open. It does not change saved course progress.

4

Catch the common trap

The usual error is to believe that the bigger charge pushes harder — that a 5.0 nC sphere must shove a 0.50 nC sphere more than it is shoved back. Look at what the law actually contains: the product |q₁||q₂|, and a product does not care which factor is larger. Put those two charges 2.0 cm apart and each feels 56 µN, the same number, in opposite directions along the same line. Swap the two spheres over and not a single term in the formula changes. Newton's third law is not an extra rule pasted onto Coulomb's law; it is already inside the symmetry of q₁q₂. The tenfold difference in charge alters the size of the force not at all — it shows up only afterwards, in how far each sphere actually moves.

5

Practice & worked examples

3 authored examples. Make an attempt, then reveal the reasoning one step at a time.

EasyExample 1

A small sphere carrying q₁ = +4.0 nC is held 3.0 cm from a second small sphere carrying q₂ = −6.0 nC. Find the magnitude of the electrostatic force on each sphere and state its direction.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 4 steps revealed.

MediumExample 2

A charge q₁ = +2.50 nC sits at the origin and a charge q₂ = −7.00 nC sits at (40.0 mm, 30.0 mm). Find the force on q₂ as components, then as a magnitude and a direction.

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

HardExample 3

A torsion balance holds two fixed charged spheres and records F = 1.15 mN at a centre-to-centre separation of 20.0 mm and F = 0.288 mN at 40.0 mm. (a) Test the exponent. (b) Find q₁q₂. (c) If the two charges are equal in magnitude, find |q|. (d) Each sphere has radius 3.0 mm — is the point-charge model safe?

Sketch your answer or reasoning, then compare it with the authored solution. Your writing is not automatically graded or saved.

0 of 5 steps revealed.

6

Quick check

Select an answer and explain it before checking.

Two small charged spheres held at rest 5.0 cm apart attract each other with a force of 48 µN. The charge on one sphere is then tripled while the other sphere is left alone, and the separation is increased to 10.0 cm. What force does each sphere feel now?
7

Review & continue

Coulomb's law says that two point charges at rest push or pull each other along the line joining them, with a force proportional to the product of their charge magnitudes and inversely proportional to the square of their separation.

  • Explain the relationship without looking at the equation.
  • Check a sign, a unit and a model assumption in your working.
  • Return to the lab or worked example if a step is still unclear.

Optional supporting lessons

These chapter resources can help with earlier ideas; they are not additional required Physics II completion tasks.

Extra challenging questions

Connect several ideas, explore supplied data, and compare your reasoning with a worked solution.